Spock Test, only check if method is called and do not execute it
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If you are not mocking the service itself, you would need to do something like this (be aware of passing the proper parameters when using metaClass:
def "Test"() {
setup:
def calls = 0
service.metaClass.innerMethod = { p1 -> calls++ }
when:
service.doSomething("[email protected]")
then:
calls==1
}
and if you are mocking the service,
def "Test"() {
when:
service.doSomething("[email protected]")
then:
1 * service.innerMethod(_)
}
Comments
-
Alexander Kiefer almost 2 years
In our Spock tests we want to check if the correct path in our software is selected. But we do not want to test the function of the methods which are called (this is done in separate tests)
def "Test"() { setup: service.metaClass.innerMethod = { -> return null } when: service.doSomething("[email protected]") then: 1 * service.innerMethod(*_) }
This test always fails, because the code in the
innerMethod
is called and the invocations of the method calls in theinnerMethod
are counted and not the invocation of the methodinnerMethod
| Too few invocations for: 1 * service.innerMethod(*_) (0 invocations) Unmatched invocations (ordered by similarity): 1 * secondService.doSomething()
How can I just get the invocation of innerMethod and mock the complete function away?