SQLAlchemy JSON column - how to perform a contains query
Solution 1
Use JSON_CONTAINS(json_doc, val[, path])
:
from sqlalchemy import func
# JSON_CONTAINS returns 0 or 1, not found or found. Not sure if MySQL
# likes integer values in WHERE, added == 1 just to be safe
session.query(Story).filter(func.json_contains(Story.section_ids, X) == 1).all()
As you're searching an array at the top level, you do not need to give path. Alternatively beginning from 8.0.17 you can use value MEMBER OF(json_array)
, but using it in SQLAlchemy is a little less ergonomic in my opinion:
from sqlalchemy import literal
# self_group forces generation of parenthesis that the syntax requires
session.query(Story).filter(literal(X).bool_op('MEMBER OF')(Story.section_ids.self_group())).all()
Solution 2
For whoever get here, but is using PostgreSQL instead:
your fields should be of the type sqlalchemy.dialects.postgresql.JSONB
(and not sqlalchemy_utils.JSONType) -
Then you can use the Comparator
object that is associated with the field with its contains
(and others) operators.
Example:
Query(Mymodel).filter(MyModel.managers.comparator.contains(["[email protected]"]))
(note that the contained part must be a JSON fragment, not just a string)
Shoham
Updated on June 06, 2022Comments
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Shoham almost 2 years
I have the following table in mysql(5.7.12):
class Story(db.Model): sections_ids = Column(JSON, nullable=False, default=[])
sections_ids is basicly a list of integers [1, 2, ...,n]. I need to get all rows where sections_ids contains X. I tried the following:
stories = session.query(Story).filter( X in Story.sections_ids ).all()
but it throws:
NotImplementedError: Operator 'contains' is not supported on this expression
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Ilja Everilä over 7 yearsYou can read about generic functions in SQLA here.
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Shoham over 7 yearsAre you sure thats the right syntax? its not working for me... no error is raised... it just not continue to the next line...
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Shoham over 7 yearsShould be str(X)... (in my case X was int and only when casting to string it worked). THANKS!
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Toufeeq over 3 yearsI want to do the searching at 2nd level, how to specify the path?
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Ilja Everilä over 3 years@toufeeq Pass it as the 3rd argument.
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Toufeeq over 3 years@IljaEverilä I mean to ask, how to pass the wildcard path $[*].some_field. Since * is not allowed in sqlalchemy query
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Ilja Everilä over 3 yearsIt is MySQL that does not allow a wildcard in a json path with
JSON_CONTAINS
. Instead you could search for an object with the required key-value pair:func.json_contains(Foo.bar, func.json_object("some_field", "some_value"))
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Dave over 3 years
MyModel.managers
in this case is the column name ("managers"), not some special keyword.