Start session after destroy php

Question

I have a logout file for my web application. I would like to create a session after the logout so that I can echo a logout success message. My logout code works but I am unable to create a new session after destroying the previous one.

What is the best way to do this, see code:

//LOGOUT.PHP
session_start(); 

//// unset all $_SESSION variables
session_regenerate_id();
session_unset();
session_destroy();

$_SESSION['logoutsuccess'] = 'You have successfully logged out.';
header("Location: /login/");
exit;


//LOGIN.PHP (ECHO SUCCESS MESSAGE)

if(isset($_SESSION['logoutsuccess']))
{
echo '<div class="success">'.$_SESSION['logoutsuccess'].'</div>'; 
unset($_SESSION['logoutsuccess']);
}

I would like to avoid passing variables in the url if possible.

Solution 1

Instead of trying to store it as a session variable, you could check the referer and check for /logout/

if(strpos($_SERVER['HTTP_REFERER'], 'logout')  !== false) {
  echo 'You have successfully logged out.';
}

Solution 2

Call session_start() again after session_destroy()?

Solution 3

Just start a new session:

session_start();
session_destroy();
session_start();
$_SESSION['food'] = 'pizza';