Storing UUID as string in mysql using JPA

16,244

Solution 1

just use @org.hibernate.annotations.Type(type="uuid-char")

There is three levels of data types:
- Java types
- Hibernate's types
- Database Specific types.

Hibernate data type presentation is a bridge between Java data type and Database types to be independent from database.

You can check this mappings. As you can find there java.util.UUID can be mapped to diferent types (binary or char/varchar). uuid-binary is key to hibernate's UUIDBinaryType, you get this type by default and it will be mapped to BINARY of your database.

If you want to get CHAR type under your UUID, you should explain to hibernate that you want his UUIDCharType. To do that you use uuid-char key and as you can check in JavaDoc of @Type annotation: Defines a Hibernate type mapping.. So, you use annotation to explain hibernate which bridge it should use.

Solution 2

I had the same problem in my last project (spring-boot:2.5.3 + mariaDB).
So I added the following annotation @Type(type = "org.hibernate.type.UUIDCharType") to fix it.

import org.hibernate.annotations.GenericGenerator;
import org.hibernate.annotations.Type;

import javax.persistence.*;
import java.util.UUID;
/** imports */

@Entity()
@Table(name = "users")
public class User {
    @Id
    @GeneratedValue(generator = "UUID")
    @GenericGenerator(name = "UUID", strategy = "org.hibernate.id.UUIDGenerator")
    @Column(name = "uuid", columnDefinition = "char(36)")
    @Type(type = "org.hibernate.type.UUIDCharType")
    private UUID uuid;

   /** ... */
}

The purpose of the hibernate annotation @Type is to define the type of data stored in database and it's compatible with the previous line @Column(name = "uuid", columnDefinition = "char(36)")

While googling it, I noticed that mariaDB & MySQL have the same issue.

You can see here more examples in different use cases for org.hibernate.annotations.Type

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Sunil Rao
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Sunil Rao

Enthusiastic learner

Updated on June 03, 2022

Comments

  • Sunil Rao
    Sunil Rao almost 2 years

    I came across a blog of using UUID with Hibernate and MySql. Now the problem is, whenever I take a look at the database the ID's will be non-readable format (binary-16). How can I store UUID as a readable format like 7feb24af-fc38-44de-bc38-04defc3804fe instead of ¡7ôáßEN¹º}ÅÑs

    I was using this code

    @Id
    @GeneratedValue( generator = "uuid2" )
    @GenericGenerator( name = "uuid2", strategy = "uuid2" )
    @Column( name = "id", columnDefinition = "BINARY(16)" )
    private UUID id;
    

    And the result is ¡7ôáßEN¹º}ÅÑs. But I want it as readable UUID so I used the following code which didn't help me

    @Id
    @GeneratedValue( generator = "uuid2" )
    @GenericGenerator( name = "uuid2", strategy = "uuid2" )
    @Column( name = "id", columnDefinition = "CHAR(32)" )
    private UUID id;
    

    How to save the UUID as a string instead of binary(16) without changing the java type UUID