Subclass - Arguments From Superclass
There's no magic happening! __init__
methods work just like all others. You need to explicitly take all the arguments you need in the subclass initialiser, and pass them through to the superclass.
class Superclass(object):
def __init__(self, arg1, arg2, arg3):
#Initialise some variables
#Call some methods
class Subclass(Superclass):
def __init__(self, subclass_arg1, *args, **kwargs):
super(Subclass, self).__init__(*args, **kwargs)
#Call a subclass only method
When you call Subclass(arg1, arg2, arg3)
Python will just call Subclass.__init__(<the instance>, arg1, arg2, arg3)
. It won't magically try to match up some of the arguments to the superclass and some to the subclass.
donopj2
Updated on June 14, 2022Comments
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donopj2 about 2 years
I'm a little confused about how arguments are passed between Subclasses and Superclasses in Python. Consider the following class structure:
class Superclass(object): def __init__(self, arg1, arg2, arg3): #Inilitize some variables #Call some methods class Subclass(Superclass): def __init__(self): super(Subclass, self).__init__() #Call a subclass only method
Where I'm having trouble is understanding how arguments are passed between the Superclass and Subclass. Is it necessary to re-list all the Superclass arguments in the Subclass initializer? Where would new, Subclass only, arguments be specified? When I try to use the code above to instantiate a Subclass, it only expects 1 argument, not the original 4 (including self) I listed.
TypeError: __init__() takes exactly 1 argument (4 given)