subprocess.call env var

Question

I'm using Popen because I need the env, like this:

Popen(
    ["boto-rsync", "..."],
    env={"PATH":"/Library/Frameworks/Python.framework/Versions/2.7/bin/"},
    )

The problem is Popen runs the command as a new thread. Is there any way that I could pass the env to subprocess.call or prevent Popen from creating a new thread? Thanx

Solution

You can use env with call in the exact same way as with popen:

subprocess.call(
    ["boto-rsync", "..."],
    env={"PATH":"/Library/Frameworks/Python.framework/Versions/2.7/bin/"},
    )

Comments

[AliBZ]

Thanx, I don't know why I didn't try it ! I think I couldn't find the option.

[Colin D Bennett]

@AliBZ the documentation for subprocess.call is not clear on that point -- the only indication that other keyword args are supported is the tiny little asterisk in subprocess.call(args, *, stdin=None, stdout=None, stderr=None, shell=False)

[jfs]

@AliBZ: to be clear: subprocess.call(cmd) is just subprocess.Popen(cmd).wait() i.e., you may pass to call() all arguments that you may pass to Popen().