Swift 3 WKWebView 'URLRequest'; did you mean to use 'as' to explicitly convert? ( BUG )
11,959
Use URL and URLRequest instead:
let url = URL(string: "https://facebook.com")!
webView.load(URLRequest(url: url))
This is quite similar to https://stackoverflow.com/a/37812485/2227743: you either use NSURL and have to downcast it as URL, or you directly use the new Swift 3 structs.
If you follow the error message, your example would become:
let url = NSURL(string: "https://facebook.com")!
webView.load(URLRequest(url: url as URL))
It could be even worse:
let url = NSURL(string: "https://facebook.com")!
webView.load(NSURLRequest(url: url as URL) as URLRequest)
All this works but of course it's much better to start using URL and URLRequest in Swift 3, without using all this downcasting.
Comments
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SwiftDeveloper almost 2 years
Hello when I use WKWebView codes with Swift 3 gives me this error
'URLRequest'; did you mean to use 'as' to explicitly convert?
I think this is bug I need help or ideas ? My codes under below Thanks
import UIKit import WebKit class SocialsViewController: UIViewController, WKNavigationDelegate { var webView = WKWebView() override func viewDidLoad() { super.viewDidLoad() let url = NSURL(string: "https://facebook.com")! webView.loadRequest(NSURLRequest(url: url)) webView.allowsBackForwardNavigationGestures = true } }
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Eric Aya over 7 yearsNo. In Swift 3, it's
load
, notloadRequest
, and I've already answered with a correct solution. -
Nirmal Bajpai over 7 yearsYes! Mr Eric you already provide correct solution. I just change name to differentiate argument "url" and variable of URL struct "myUrl". which is little confusing for freshers. Thanks