Swift: Extra argument 'error' in call
Solution 1
With Swift 2, the signature for NSJSONSerialization
has changed, to conform to the new error handling system.
Here's an example of how to use it:
do {
if let jsonResult = try NSJSONSerialization.JSONObjectWithData(data, options: []) as? NSDictionary {
print(jsonResult)
}
} catch let error as NSError {
print(error.localizedDescription)
}
With Swift 3, the name of NSJSONSerialization
and its methods have changed, according to the Swift API Design Guidelines.
Here's the same example:
do {
if let jsonResult = try JSONSerialization.jsonObject(with: data, options: []) as? [String:AnyObject] {
print(jsonResult)
}
} catch let error as NSError {
print(error.localizedDescription)
}
Solution 2
Things have changed in Swift 2, methods that accepted an error
parameter were transformed into methods that throw that error instead of returning it via an inout
parameter. By looking at the Apple documentation:
HANDLING ERRORS IN SWIFT: In Swift, this method returns a nonoptional result and is marked with the throws keyword to indicate that it throws an error in cases of failure.
You call this method in a try expression and handle any errors in the catch clauses of a do statement, as described in Error Handling in The Swift Programming Language (Swift 2.1) and Error Handling in Using Swift with Cocoa and Objective-C (Swift 2.1).
The shortest solution would be to use try?
which returns nil
if an error occurs:
let message = try? NSJSONSerialization.JSONObjectWithData(receivedData, options:.AllowFragments)
if let dict = message as? NSDictionary {
// ... process the data
}
If you're also interested into the error, you can use a do/catch
:
do {
let message = try NSJSONSerialization.JSONObjectWithData(receivedData, options:.AllowFragments)
if let dict = message as? NSDictionary {
// ... process the data
}
} catch let error as NSError {
print("An error occurred: \(error)")
}
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kaanmijo
Updated on October 04, 2020Comments
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kaanmijo over 3 years
I'm currently developing my first iOS app using Swift 2.0 and Xcode Beta 2. It reads an external JSON and generates a list in a table view with the data. However, I'm getting a strange little error that I can't seem to fix:
Extra argument 'error' in call
Here is a snippet of my code:
let task = session.dataTaskWithURL(url!, completionHandler: {data, response, error -> Void in print("Task completed") if(error != nil){ print(error!.localizedDescription) } var err: NSError? if let jsonResult = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: &err) as? NSDictionary{ if(err != nil){ print("JSON Error \(err!.localizedDescription)") } if let results: NSArray = jsonResult["results"] as? NSArray{ dispatch_async(dispatch_get_main_queue(), { self.tableData = results self.appsTableView!.reloadData() }) } } })
The error is thrown at this line:
if let jsonResult = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: &err) as? NSDictionary{
Can someone please tell me what I'm doing wrong here?
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Dharmbir Singh about 9 yearsThis line doesn't giving this error i think may b you are getting in different line.
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Race B about 9 yearsWith 2.0 you need to create a
do
catch
block.error
is no longer a parameter withNSJSONSerialization
. There are a number of other answers to this question here. Look for do, catch with Swift 2.0
-
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jeffery_the_wind about 8 yearsI am using swift 2.2, and tried your first version. It is compiling correctly but it is dying silently, does not hit either of the the
print
lines. When I remove theif
part in front ofjsonResult
and run I can infer that the jsonResult is being set asnil
no errors. I am sure the data starts as a valid json string... -
Eric Aya about 8 years@jeffery_the_wind Your JSON is probably different from what you think. Try this: stackoverflow.com/a/33510776/2227743
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jeffery_the_wind about 8 yearsThanks, yes that was it! Replacing
as? NSDictionary
withas? NSArray
in your first example works for me.