Symfony2 - How to render a view from another controller
Solution 1
I have found the solution, simply use the forward function by specifying the controller and the action nanme:
return $this->forward('MerrinMainBundle:Homepage:Index', array('flash_message'=>$flash_message));
Solution 2
I believe the checking should not be done in the Security controller. Right place in my opinion is a separate validator service or right in the entity which uses the email address.
But to your question, you can call another controller's action with $this->forward() method:
public function indexAction($name)
{
$response = $this->forward('AcmeHelloBundle:Hello:fancy', array(
'name' => $name,
'color' => 'green',
));
return $response;
}
The sample comes from symfony2 documentation on: http://symfony.com/doc/2.0/book/controller.html#forwarding
Milos Cuculovic
Masters degree in Embedded and comunicant systems.
Updated on June 04, 2022Comments
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Milos Cuculovic almost 2 years
I have two controllers, homepage and Security.
In the homepage, I am displaying one view and in the security, I am doing some things, and one of them is the email address validation.
What I would like is that when the email validation code is not valid, display the homepage with a flash message. For that, I will have to render the indexAction of the HomepageController, from the Security controller, by giving him as parameter the flash message.
How can this be done? Can I render a route or an action from another controleller?
Thank you in advance.