SymPy: Limit symbol/variable to interval
Solution 1
You can specify the bounds as inequalities such as x >= lb
and x <= ub
, for example:
from sympy.solvers import solve
from sympy import Symbol
x = Symbol('x')
solve([x >= 0.5, x <= 3, x**2 - 1], x)
Here we search for a solution of equation x**2 == 1
such that x
is in the interval [0.5, 3]
.
Solution 2
As for simplification, you want refine
. Unfortunately, it doesn't yet support using inequality syntax, so you'll have to use Q.positive
or Q.negative
(or Q.nonpositive
or Q.nonnegative
for non-strict inequalities). The most common simplification that it handles is sqrt(x**2) = x
if x >= 0
.
>>> refine(sqrt((x - 1)**2), Q.positive(x - 1))
x - 1
>>> refine(sqrt((x - 1)**2), Q.positive(x))
Abs(x - 1)
Note in the second case you still get a simpler answer because it at least knows that x - 1
is real under the given assumptions.
If your assumptions are as simple as "x
is positive" or "x
is negative", the best chance for success is to define it on the Symbol itself, like
>>> Symbol('x', positive=True)
>>> sqrt(x**2)
x
Solution 3
Now you can use solveset
In [3]: solveset(x**2 - 1, x, Interval(0.5, 3))
Out[3]: {1}
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Se Norm
Updated on September 15, 2022Comments
-
Se Norm over 1 year
Using SymPy, is it possible to limit the possible values of a symbol/variable to a certain range? I now I can set some properties while defining symbols, like
positive=True
, but I need more control, i.e. I need to set it to be in the interval [0,1]. This assumption should then be used for solving, simplifying etc. -
Se Norm over 10 yearsThanks, that works. However, I need the same for multiple variables at the same time, which raises NotImplementedError: only univariate inequalities are supported. Too bad...
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ρяσѕρєя K almost 8 yearsAdd some explanation with answer for how this answer help OP in fixing current issue
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Se Norm almost 8 yearsDoes that work for multiple variables and inequalities as well?