SyntaxError: Unexpected Identifier in Chrome's Javascript console
316,447
Solution 1
The comma got eaten by the quotes!
This part:
("username," visitorName);
Should be this:
("username", visitorName);
Aside: For pasting code into the console, you can paste them in one line at a time to help you pinpoint where things went wrong ;-)
Solution 2
Replace
var myNewString = myOldString.replace ("username," visitorName);
with
var myNewString = myOldString.replace("username", visitorName);
Solution 3
I got this error Unexpected identifier
because of a missing semi-colon ;
at the end of a line. Anyone wandering here for other than above-mentioned solutions, This might also be the cause of this error.
Author by
mjmitche
Updated on July 09, 2022Comments
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mjmitche almost 2 years
I tested this javascript in Chrome's Javascript console and it returned
SyntaxError: Unexpected Identifier
.I got this code from a tutorial and was just testing Chrome's console so i expected it to work, unless I'm using the console wrong?
Code:
var visitorName = "Chuck"; var myOldString = "Hello username. I hope you enjoy your stay username."; var myNewString = myOldString.replace ("username," visitorName); document.write("Old String = " + myOldString); document.write("<br/>New string = " + myNewString);
Output:
SyntaxError: Unexpected identifier
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Kobi over 13 yearsYou really should point out the problem. The OP didn't notice the comma on his/her own code, and isn't likely to spot the change. From a quick look, it looks like you're suggesting to use single quoted string instead of double quoted, which can be confusing - they are the same in JavaScript, but not in all languages (PHP, for one).
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ashish.chotalia over 13 yearsI tried to place myOldString.replace('username', visitorName); in bold but some how if you are placing your code in code section it didn't output it bold.
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Admin over 13 yearsYou can still edit your answer, of course. (Code's already bolded on SO.)
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totymedli about 8 yearsIt is also a good idea to use some kind of hinter or an IDE that has syntax validation.
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Mr Megamind over 7 yearsIn my case it was the change of API version, I changed from x.7 to x.8 and it worked. Hope this helps someone