Tensorflow indexing with boolean tensor


Solution 1


ones = tf.ones_like(x) # create a tensor all ones
mask = tf.greater(x, ones) # boolean tensor, mask[i] = True iff x[i] > 1
slice_y_greater_than_one = tf.boolean_mask(y, mask)

See tf.boolean_mask

EDIT: another (better ?) way to do it:

import tensorflow as tf

x = tf.constant([1, 2, 0, 4])
y = tf.Variable([1, 2, 0, 4])
mask = x > 1
slice_y_greater_than_one = tf.boolean_mask(y, mask)

with tf.Session() as sess:
    print (sess.run(slice_y_greater_than_one)) # [2 4]

Solution 2

I would not say it is completely not implemented. How's that for a double negative?

Tensorflow actually supports quite a lot of slicing and dicing, although the syntax may be slightly less pretty. For example, if you want to create a new array which is equal to y when x>1 but equal to 0 otherwise, you can definitely do that. Check out comparison operators e.g.

masked = tf.greater(x,1)
zeros = tf.zeros_like(x)
new_tensor = tf.where(masked, y, zeros)

If, on the other hand, you want to make a new array which contains only the guys where x>1 you can do that by combining where with the gather function. Details for gather can be found at


PS. Of course, x>1 is not differentiable with respect to x... tf may be great, but it doesn't work magic :).

Solution 3

This is not implemented at this moment, here's GitHub issue tracking the progress -- https://github.com/tensorflow/tensorflow/issues/206

Solution 4

Was looking for similar capability to reduce a TensorFlow.js tensor by a defined criteria, but TensorFlow.js does not have the boolean_mask function. After much hair pulling and teeth gnashing, cooked up the following, which essentially sums up the total number of true criteria, and then simply selects the topk values to create the subset tensor.

const a = tf.tensor1d([1, 2, 0, 4]);
const b = a.greater(1).sum().get();
const {values, indices} = tf.topk(a, b);
values.print();   # 4,2
indices.print();  # 3,1

And to create a subset tensor of values less than or equal to 1, it's a matter of using tf.neg on the tensor as there is no bottomk function, and then after obtaining the subset tensor via topk, applying tf.neg again to restore the original values.

Solution 5

tf.boolean_mask does the job, but on some platforms like Raspberry Pi or OSX, the operation is not supported in Tensorflow wheel distributions (Check this tf.boolean_mask not supported on OSX. So an alternative is to use where and gather as @Jackson Loper suggested. For example:

x = tf.Variable([1, 2, 0, 4])
ix = tf.where(x > 1)
y = tf.gather(x, ix)

with tf.Session() as sess:

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Updated on November 28, 2020


  • pythonic metaphor
    pythonic metaphor over 2 years

    In numpy, with two arrays of the same shape, x and y, it is possible to do slices like this y[x > 1]. How do you achieve the same result in tensorflow? y[tf.greater(x, 1)] doesn't work and tf.slice doesn't support anything like this either. Is there a way to index with a boolean tensor right now or is that currently unsupported?

  • Xander Dunn
    Xander Dunn over 6 years
    But both select and where take a boolean mask as an input. How does one take the tensor x as an input and produce a boolean mask that's True where x > 1?
  • Xander Dunn
    Xander Dunn over 6 years
  • Xander Dunn
    Xander Dunn over 6 years
    It looks like I'm looking for the comparison operators: tensorflow.org/versions/r0.11/api_docs/python/…