The issue of * in Command line argument
Solution 1
That's because *
is a shell wildcard: it has a special meaning to the shell, which expands it before passing it on to the command (in this case, java
).
Since you need a literal *
, you need to escape it from the shell. The exact way of escaping varies depending on your shell, but you can try:
java ProgramName 5 3 "*"
Or:
java ProgramName 5 3 \*
By the way, if you want to know what the shell does with the *
, try printing the content of String[] args
to your main
method. You'll find that it will contain names of the files in your directory.
This can be handy if you need to pass some filenames as command line arguments.
See also
-
For example, if a directory contains two files,
a.log
andb.log
then the commandcat *.log
will be expanded by the shell tocat a.log b.log
-
In Bourne shell (
sh
), the asterisk (*
) and question mark (?
) characters are wildcard characters expanded via globbing. Without a preceding escape character, an*
will expand to the names of all files in the working directory that don't start with a period if and only if there are such files, otherwise*
remains unexpanded. So to refer to a file literally called"*"
, the shell must be told not to interpret it in this way, by preceding it with a backslash (\
).
Solution 2
Under MS WINDOWS not quite true: "java.exe" silently expands command line arguments with the wildcards
- *
- ?
- [abc]
, but only in the last component, so
a/*/*
does not work as you may expect.
It also ignores the entries "." and "..", but does honor other file names starting with ".".
To avoid misunderstandings: If I look at the command line of the running JAVA process with PROCEXP, I see the unexpanded args!
I found no way to work around this. In other words: As long as you have at least one file or directory in the current directory, "java Calc 3 * 7" will NOT work!
This is VERY ugly, and seems to always having been there in all JRE versions up to and including Java 8.
Does anybody have an idea how to disable Java's nasty command line expansion?
Solution 3
* has special meaning in shell interpreters. How to get a * literally is depending on what shell interpreter you are using. For Bash, you should put single quotes around the *, i.e. '*', instead of double quotes like "*".
Solution 4
Use single quotes:
java FooBar 5 3 '*'
This works with most of the popular shells (including bash and ksh).
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Updated on June 04, 2022Comments
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Admin about 2 years
I wrote a program in Java that accepts input via command line arguments. I get an input of two numbers and an operator from the command line. To multiply two numbers, I have to give input as e.g.
5 3 *
, but it's not working as written.Why is it not accepting
*
from the command line? -
Harry Johnston about 10 yearsFor completeness, and since the OP didn't mention any particular operating system, note that in Windows globbing is the responsibility of the application, not the shell. It is typically handled by the application's runtime library.
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philwalk about 8 yearsI agree, this feature can be nasty, but it's a practical requirement if java command line tools are to be relatively OS-agnostic. However, there doesn't seem to be any system.property to disable it, and that makes it quadruple nasty (sigh).
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philwalk about 8 yearsBTW, you can double quote the asterisk from within a cmd.exe session and it does what you would expect, but if running from within a cygwin BASH session, there doesn't seem to be any way of doing the same thing. The weird part is I've verified that the problem occurs somewhere in java, not in the shell environment (as you said). See my notes here: stackoverflow.com/questions/37037375
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philwalk about 8 yearsit turns out that the Windows jvm performs its' own globbing internally under some circumstances, see stackoverflow.com/questions/37037375
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Hashbrown over 6 yearsthis issue also turns up calling from PowerShell, regardless of escaping/quoting