The type initializer for 'Emgu.CV.CvInvoke' threw an exception

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Solution 1

You should solve CVInvoke exception by following suggestions outlined in emgu official wiki:

http://www.emgu.com/wiki/index.php/Download_And_Installation#The_type_initializer_for_.27Emgu.CV.CvInvoke.27_threw_an_exception.

Solution 2

Here's how I could solve the problem: Copy the x86 (or x64 on 64-bit OS) folder address under "bin" folder where your Emgu is installed. Mine is: C:\Emgu\emgucv-windows-universal-gpu 2.4.9.1847\bin\x86

Then paste this address here: Control Panel>System>Advanced System Settings>Environment Variables> in system variables click on "Path" and click edit > add a semicolon to the end of the string there and paste the address you've just copied to clipboard after that semicolon > click on the OKs.

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pitumalkani
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pitumalkani

Updated on June 19, 2022

Comments

  • pitumalkani
    pitumalkani about 2 years

    I have written simple program to open image and show image in VS 2010 in C# using EmguCV but I am getting the following exception:

    The type initializer for 'Emgu.CV.CvInvoke' threw an exception.

    at line Image<Bgr, Byte> myimg = new Image<Bgr, Byte>(openfile.FileName);

    here is my code..

    using System;
    using System.Collections.Generic;
    using System.ComponentModel;
    using System.Data;
    using System.Drawing;
    using System.Linq;
    using System.Text;
    using System.Windows.Forms;
    using Emgu.CV;
    using Emgu.Util;
    using Emgu.CV.Structure;
    
    namespace imgdisplay2
    {
        public partial class Form1 : Form
        {
            public Form1()
            {
                InitializeComponent();
            }
    
            private void imageBox1_Click(object sender, EventArgs e)
            {
            }
    
            private void button1_Click(object sender, EventArgs e)  
            {
                OpenFileDialog openfile = new OpenFileDialog();
                if (openfile.ShowDialog() == DialogResult.OK)
                {
                    // imageBox1 =new Emgu.CV.UI.ImageBox() ;
                    Image<Bgr, Byte> myimg = new Image<Bgr, Byte>(openfile.FileName);
                    pictureBox1.Image = myimg.ToBitmap();
                    //imageBox1.Image =myimg ;
                }  
            }
    
            private void pictureBox1_Click(object sender, EventArgs e)
            {
            }
        }
    }