There is an error in XML document (0, 0) during deserialization

10,541

ok solved,

using (Stream loadstream = new FileStream(loadpath, FileMode.Open))
        {
            XmlSerializer serializer = new XmlSerializer(typeof(FormSaving));
            abc = (FormSaving)serializer.Deserialize(loadstream);

        }

should have been FileMode.Open instead of FileMode.Create

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jeremychan
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jeremychan

Updated on June 04, 2022

Comments

  • jeremychan
    jeremychan almost 2 years

    i have the following code to for xml serialization.

        public class FormSaving
        {
            private string major;
    
            public string Majorversion
            {
                get;
    
                set;
    
            }
        }
    
    
    
        private void SaveButton_Click(object sender, RoutedEventArgs e)
        {
            string savepath;
            SaveFileDialog DialogSave = new SaveFileDialog();
            // Default file extension
            DialogSave.DefaultExt = "txt";
            // Available file extensions
            DialogSave.Filter = "XML file (*.xml)|*.xml|All files (*.*)|*.*";
            // Adds a extension if the user does not
            DialogSave.AddExtension = true;
            // Restores the selected directory, next time
            DialogSave.RestoreDirectory = true;
            // Dialog title
            DialogSave.Title = "Where do you want to save the file?";
            // Startup directory
            DialogSave.InitialDirectory = @"C:/";
            DialogSave.ShowDialog();
            savepath = DialogSave.FileName;
            DialogSave.Dispose();
            DialogSave = null;
    
            FormSaving abc = new FormSaving();
            abc.Majorversion = MajorversionresultLabel.Content.ToString();
            using (Stream savestream = new FileStream(savepath, FileMode.Create))
            {
    
                    XmlSerializer serializer = new XmlSerializer(typeof(FormSaving));
                    serializer.Serialize(savestream, abc);
            }
    
    
    
        }
    
    
        private void LoadButton_Click(object sender, RoutedEventArgs e)
        {
    
    
            Stream checkStream = null;
            Microsoft.Win32.OpenFileDialog DialogLoad = new Microsoft.Win32.OpenFileDialog();
            DialogLoad.Multiselect = false;
            DialogLoad.Filter = "XML file (*.xml)|*.xml|All files (*.*)|*.*";
            if ((bool)DialogLoad.ShowDialog())
            {
                try
                {
                    if ((checkStream = DialogLoad.OpenFile()) != null)
                    {
                        loadpath = DialogLoad.FileName;
                        checkStream.Close();
                    }
                }
                catch (Exception ex)
                {
                    System.Windows.MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
                }
            }
            else
            {
                System.Windows.MessageBox.Show("Problem occured, try again later");
            }
    
            FormSaving abc;
            using (Stream loadstream = new FileStream(loadpath, FileMode.Create))
            {
                XmlSerializer serializer = new XmlSerializer(typeof(FormSaving));
                abc = (FormSaving)serializer.Deserialize(loadstream);
    
            }
    
            MajorversionresultLabel.Content = abc.Majorversion;
        }
    

    When i press the SaveButton, my label.content is saved into an xml file. However when i press the load button to load this xml file, i get the error "There is an error in XML document (0, 0)". I went to open my xml file after pressing the load button, it becomes blank and everything got erased. Can anyone help me fix this load button error?

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