TypeError Too many Arguments

Question

When running this code it appears with an error that there are too many arguments in line 8. I'm unsure on how to fix it.

#Defining a function to raise the first to the power of the second.
def power_value(x,y):
    return x**y

##Testing 'power_value' function
#Getting the users inputs
x = int(input("What is the first number?\n"))
y = int(input("What power would you like to raise",x,"to?\n"))

#Printing the result
print (x,"to the power of",y,"is:",power_value(x,y))

Resulting in a TypeError...

     Traceback (most recent call last):
  File "C:\[bla location]", line 8, in <module>
    y = int(input("What power would you like to raise",x,"to?\n"))
TypeError: input expected at most 1 arguments, got 3

Solution 1

The issue is that the python input() function was only ready to accept one parameter - the prompt string, but you passed in three. To solve this issue, you just need to combine all three pieces into one.

You can use the % operator to format string:

y = int(input("What power would you like to raise %d to?\n" %x,))

Or use the new way:

y = int(input("What power would you like to raise {0} to?\n".format(x)))

You can find the document here.

Solution 2

Change your y input line to

y = int(input("What power would you like to raise" + str(x) + "to?\n"))

So you will concatenate the three substrings into a single string.

Solution 3

you need to specify x variable :

using format

y = int(input("What power would you like to raise {}to?\n".format(x)))

or

y = int(input("What power would you like to raise %d to?\n"%x)))

Comments

[UrbanConor]

Yes I have used comas to separate them when it should be like that. Thanks :D

[Matthias]

No, it shouldn't be like that. Use format as others suggested.

[karthikr]

Please provide more context to the answer. Moreover, i still see syntax errors in the answer.

[Cory Kramer]

@Matthias "it shouldn't"? Why is that? It works fine.

[Matthias]

It works, but it lacks flexibility. With format you can control the result much better. Additionally: In your example you're missing the blanks around the number. Using a format-string you would see it at once.

[UrbanConor]

Thanks, it just I'm not to sure on how the '%' operator works