Unable to set div.style.left and div.style.top css properties via JavaScript
You have forgotten "px":
div.style.left = (e.pageX + 25) + 'px';
div.style.top = (e.pageY -10) + 'px';
You might also want to add div.style.position = "absolute";
If you think there's any chance that e.pageX
or e.pageY
will be strings rather than numbers, throw a parseInt
in:
div.style.left = (parseInt(e.pageX, 10) + 25) + 'px';
div.style.top = (parseInt(e.pageY, 10) - 10) + 'px';
Ramon Wenger
Updated on June 26, 2022Comments
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Ramon Wenger about 2 years
I ran in a very confusing problem today
I have a canvas, and a div, like this
<canvas id="canvas" width="800" height="400"></canvas> <div id="xy"></div>
I then set the properties of the div via a css file, e.g. position:absolute and display:none Then, i write the X/Y Position in the div via JS and try to set the properties of the div so that the div follows the mouse around, like this
var div = document.getElementById("xy"); var x = e.pageX - this.offsetLeft - 1; var y = e.pageY - this.offsetTop - y0 - 0.5; div.style.display = "block"; div.style.left = e.pageX + 25; div.style.top = e.pageY -10; div.style.backgroundColor = "#f00";
The funny thing now is: i can set the display and backgroundColor without a problem, but the left and top properties don't work. If i delete my DOCTYPE-declaration in my HTML file though, i can modify the left and top properties without any trouble. Working without doctype is out of the question of course. Am i doing something that shouldn't be done or missing something completely obvious?
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T.J. Crowder about 12 years+1, but your
parseInt
is unnecessary or, if required, has the ending)
in the wrong place. I believee.pageX
is already a number, but if there's any chance it isn't, you want= (parseInt(e.pageX, 10) + 25) + 'px';
(Note I also put the radix on it. You almost always want to tellparseInt
specifically what radix to use.) -
ke20 about 12 yearsyes, but as it is a concatenated string it's more secure. I personally prefer :). (alright for the radix, I will use now :))
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T.J. Crowder about 12 yearsMy point is that what's there is actively wrong, not that it's not ideal. If
e.pageX
is a string (say,"10"
), thenparseInt(e.pageX + 25)
will be1025
, not35
, because when you add a number to a string, the number is converted to text and appended: jsbin.com/ekiwup -
Ramon Wenger about 12 yearsthat was just it. my head just met my desk at a high velocity. thank you very much ;) what i already had tried was + ' px', but there mustn't be a ' ' in it, i realized just now
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Ramon Wenger about 12 yearsthe parseInt isn't even necessary, it works with just (e.pageX + 25) + 'px'
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T.J. Crowder about 12 years@RamonWenger: Yeah, that's what I said up above.
pageX
andpageY
are already numbers.