Uncaught TypeError: Cannot use 'in' operator to search for 'length' in

Question

Uncaught TypeError: Cannot use 'in' operator to search for 'length' in "

This is the error I receive when I try to do a $.each to this JSON object :

{"type":"Anuncio","textos":["Probando esto","$ 20150515"],"submit":"codParameters?___DDSESSIONID\u003d14EA4721A904D6DD71591156996E29F7%3A%2FMobilTest"}

I have also tried to do the same with stringify, but I receive the same error:

{\"type\":\"Anuncio\",\"textos\":[\"Probando esto\",\"$ 20150515\"],\"submit\":\"codParameters?___DDSESSIONID\\u003d06CBEC9D1A53616EFF703A8C71FBC2B4%3A%2FMobilTest\"}"

If I remove parameters ___DDSESSIONID\\u003d06CBEC9D1A53616EFF703A8C71FBC2B4%3A%2FMobilTest from the object the $.each works fine.

Why might this be happening?

Solution 1

The in operator only works on objects. You are using it on a string. Make sure your value is an object before you using $.each. In this specific case, you have to parse the JSON:

$.each(JSON.parse(myData), ...);

Solution 2

maybe you forget to add parameter dataType:'json' in your $.ajax

$.ajax({
   type: "POST",
   dataType: "json",
   url: url,
   data: { get_member: id },
   success: function( response ) 
   { 
     //some action here
   },
   error: function( error )
   {
     alert( error );
   }
});

Solution 3

this work for me

$.each(JSON.parse("[" + data + "]"))

$.each only works on objects . if your data is an array you can change it like this

 $data = (object)$array;

Comments

[Sidd]

Please format your code, it's impossible to read it like this. You can use the {} text editor button, or indent every code line 4 spaces.

[Iván Alberto Fontalvo Salgado]

Felix, before $.each I have JSON.parse , the error appears when in the key submit have the value -> "codParameters?___DDSESSIONID\u003d14EA4721A904D6DD715911569‌​96E29F7%3A%2FMobilTe‌​st".

[Felix Kling]

Please post your code, I can't repro the error you are describing: jsfiddle.net/5asbeatq

[Felix Kling]

Don't post an answer if it isn't one. Edit your question and include the relevant code in the question.

[Mohammed Sufian]

wasted 2 hours, and finally got it working using validator.showErrors(JSON.parse(data)) , thanks a lot sir..

[Cr1xus]

I get this error for $.each("ul li",function(k,v){ ... });

[Luis Rock]

That did it to me. Thanks!

[Raju Paladiya]

Thanks @FelixKling, You saved my lot's of time. After convert string to Array it's working fine.

[Mech]

Thanks from 2020!

[Jesper]

This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review