Unexpected java SimpleDateFormat parse exception
32,164
It is a Locale issue. Use:
sdf = SimpleDateFormat("EEE MMM d HH:mm:ss z yyyy", Locale.US);
Author by
Emilio
Updated on July 22, 2022Comments
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Emilio almost 2 years
I can't understand why this few lines
Date submissionT; SimpleDateFormat tempDate = new SimpleDateFormat("EEE MMM d HH:mm:ss z yyyy"); public time_print(String time) { try { submissionT=tempDate.parse(time); } catch (Exception e) { System.out.println(e.toString() + ", " + time); } }
Cause exceptions and print out
java.text.ParseException: Unparseable date: "Tue Mar 31 06:09:00 CEST 2009", Tue Mar 31 06:09:00 CEST 2009
... while the "unparsable" time is compliant with the format string i've passed to SimpleDateFormat().. Any Idea?
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NikolaDjokic about 15 yearsIt only works because of your default Locale matches the expected one.
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golimar almost 7 yearsWould be nice if the exception message was not just "Unparseable date" but also the position in the String where it failed...