usage of double pointers as arguments
Solution 1
int **p
is a pointer to a pointer-to-int. My_Func(int **p)
works by changing the value of integer that the pointer-to-int points to i.e. int a
.
Without changing the implementation, the function will not work with a pointer-to-int parameter int *p
as there is a second level of indirection. In addition, you're setting the value to a local variable that is created on the stack. When the function is completed the memory used for the variable will be reclaimed, therefore making the value of a
invalid.
void My_Func(int **p)
{
int val = 100; // Local variable.
int *Ptr = &val; // This isn't needed.
*p = Ptr;
} // val dissapears.
Remove the second level of indirection and copy val
by value instead of pointing to it:
#include <stdio.h>
void My_Func(int *p)
{
int val = 100;
*p = val;
}
int main(void)
{
int a = 5;
My_Func(&a);
printf("The val of a is %d\n", a);
return 0;
}
Solution 2
In short, in C when you pass something as a parameter, a copy will be passed to the function. Changing the copy doesn't affect the original value.
However, if the value is a pointer, what it points to can be changed. In this case, if you want to affect the pointer, you need to pass a pointer to it down to the function.
Maddy
Updated on August 06, 2020Comments
-
Maddy almost 4 years
Please find the code snippet as shown below:
#include <stdio.h> int My_func(int **); int main() { int a =5; int *p = &a; My_Func(&p); printf("The val of *p is %d\n,*p); } void My_Func(int **p) { int val = 100; int *Ptr = &val; *p = Ptr; }
How does by using a double pointer as a argument in
my_Func
function and making change of value reflects the same in the main function but if we use a single pointer inMy_Func
does not change the value in main?Please do explain me with examples if possibleAdvanced thanks
Maddy -
Unheilig about 10 yearsI am late here, hope you don't mind I ask: I have the exact problem, I tried passing both single and double pointers and change the value within a function, in both cases, the original values did get changed. My understanding is that we need to use a double pointer to change the original value within a function. Hope you could shred some light on this. Thanks in advance.