Use a variable in a sed command
Solution 1
you need to use double quotes ("
) instead of single quotes ('
).
single quotes pass their content literally, without translating variables (expansion).
try
sed "24s/.*/\"$ct_tname\"/" file1.sas > file2.sas
btw, if you're going to be editing a file (that is if file2.sas is a temporary file), you should be using ed
instead.
Solution 2
In my case, i just remplaced single quotes by the double ones:
for a in $(cat ext.cnf); do sed -n "/$a$/p" file1 >> file2; done
For now, it's working well...
Solution 3
The problem is that when $ct_fname
is substituted, sed
sees extra /
separators, so
sed "24s/.*/"$ct_tname"/" file1.sas > file2.sas
becomes
sed "24s/.*/"%let outputfile=/user/ct_ARGUMENT1.csv;"/" file1.sas > file2.sas
and you'll get a sed
error because there are 5 /
instead of the expected 3.
Instead, change your sed
separators to an unused character like |
or :
, and either single or double quotes will work just fine:
sed '24s|.*|'$ct_tname'|' file1.sas > file2.sas
sed "24s|.*|"$ct_tname"|" file1.sas > file2.sas
Solution 4
Shell variables are not expanded inside single quotes. Try this instead:
sed "24s/.*/\"$ct_tname\"/" file1.sas > file2.sas
Solution 5
You need to use double ("
) quotes, with single ('
) quotes the value of the variable doesn't get replaced. Since you have double quotes in your replacement text, you need to escape them:
sed "24s/.*/\"$ct_tname\"/" file1.sas > file2.sas
user788171
Updated on February 13, 2020Comments
-
user788171 about 4 years
I can't seem to use a variable in a sed command, for example:
sed "24s/.*/"$ct_tname"/" file1.sas > file2.sas
I want
$ct_tname
the variable, not literally$ct_tname
, which is what I keep getting.Anybody know how to get this to work?
The problem is actually more complex and I omitted some information.
ct_fname="%let outputfile="/user/ct_"$1".csv";"
Here,
$1
is the argument passed in at the start of my bash script (sed is being run inside a bash script).This doesn't run successfully, but it does run if I replace
ct_fname
withct_fname="%let table=ct_$1;"
Is there a way to get the first
ct_fname
to be passed successfully?