Use data.table to count and aggregate / summarize a column
57,579
The post you are referring to gives a method on how to apply one aggregation method to several columns. If you want to apply different aggregation methods to different columns, you can do:
dat[, .(count = .N, var = sum(VAR)), by = MNTH]
this results in:
MNTH count var 1: 201501 4 2 2: 201502 3 0 3: 201503 5 2 4: 201504 4 2
You can also add these values to your existing dataset by updating your dataset by reference:
dat[, `:=` (count = .N, var = sum(VAR)), by = MNTH]
this results in:
> dat MNTH VAR count var 1: 201501 1 4 2 2: 201501 1 4 2 3: 201501 0 4 2 4: 201501 0 4 2 5: 201502 0 3 0 6: 201502 0 3 0 7: 201502 0 3 0 8: 201503 0 5 2 9: 201503 0 5 2 10: 201503 1 5 2 11: 201503 1 5 2 12: 201503 0 5 2 13: 201504 1 4 2 14: 201504 0 4 2 15: 201504 1 4 2 16: 201504 0 4 2
For further reading about how to use data.table syntax, see the Getting started guides on the GitHub wiki.
Comments
-
Whitebeard almost 4 years
I want to count and aggregate(sum) a column in a
data.table
, and couldn't find the most efficient way to do this. This seems to be close to what I want R summarizing multiple columns with data.table.My data:
set.seed(321) dat <- data.table(MNTH = c(rep(201501,4), rep(201502,3), rep(201503,5), rep(201504,4)), VAR = sample(c(0,1), 16, replace=T)) > dat MNTH VAR 1: 201501 1 2: 201501 1 3: 201501 0 4: 201501 0 5: 201502 0 6: 201502 0 7: 201502 0 8: 201503 0 9: 201503 0 10: 201503 1 11: 201503 1 12: 201503 0 13: 201504 1 14: 201504 0 15: 201504 1 16: 201504 0
I want to both count and sum
VAR
byMNTH
using data.table. The desired result:MNTH COUNT VAR 1 201501 4 2 2 201502 3 0 3 201503 5 2 4 201504 4 2