ValueError: unknown url type

17,877

Solution 1

You should first try to add 'http://' in front of the url. Also, do not store the results in print, as it is binding the reference to another (non callable) object.

So this line should be:

page_contents = getpage("http://www.radioreference.com/apps/audio/?ctid=5586")

This returns a file like object. To read its contents you need to use different file manipulation methods, like this:

for line in page_contents.readlines():
    print line

Solution 2

You need to pass a full URL: ie it must begin with http://.

Solution 3

Simply use http://www.radioreference.com/apps/audio/?ctid=5586 and it'll work fine.

In [24]: from urllib2 import urlopen as getpage

In [26]: print getpage("http://www.radioreference.com/apps/audio/?ctid=5586")
<addinfourl at 173987116 whose fp = <socket._fileobject object at 0xa5eb6ac>>
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17,877
Jamus
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Jamus

Updated on June 04, 2022

Comments

  • Jamus
    Jamus almost 2 years

    The title pretty much says it all. Here's my code:

    from urllib2 import urlopen as getpage
    print = getpage("www.radioreference.com/apps/audio/?ctid=5586")
    

    and here's the traceback error I get:

    Traceback (most recent call last):
      File "C:/Users/**/Dropbox/Dev/ComServ/citetest.py", line 2, in <module>
        contents = getpage("www.radioreference.com/apps/audio/?ctid=5586")
      File "C:\Python25\lib\urllib2.py", line 121, in urlopen
        return _opener.open(url, data)
      File "C:\Python25\lib\urllib2.py", line 366, in open
        protocol = req.get_type()
      File "C:\Python25\lib\urllib2.py", line 241, in get_type
        raise ValueError, "unknown url type: %s" % self.__original
    ValueError: unknown url type: www.radioreference.com/apps/audio/?ctid=5586
    

    My best guess is that urllib can't retrieve data from untidy php URLs. if this is the case, is there a work around? If not, what am I doing wrong?