View's SELECT contains a subquery in the FROM clause

129,244

Solution 1

As per documentation:

MySQL Docs

  • The SELECT statement cannot contain a subquery in the FROM clause.

Your workaround would be to create a view for each of your subqueries.

Then access those views from within your view view_credit_status

Solution 2

create view view_clients_credit_usage as
    select client_id, sum(credits_used) as credits_used 
    from credit_usage 
    group by client_id

create view view_credit_status as 
    select 
        credit_orders.client_id, 
        sum(credit_orders.number_of_credits) as purchased, 
        ifnull(t1.credits_used,0) as used 
    from credit_orders
    left outer join view_clients_credit_usage as t1 on t1.client_id = credit_orders.client_id
    where credit_orders.payment_status='Paid'
    group by credit_orders.client_id)

Solution 3

As the more recent MySQL documentation on view restrictions says:

Before MySQL 5.7.7, subqueries cannot be used in the FROM clause of a view.

This means, that choosing a MySQL v5.7.7 or newer or upgrading the existing MySQL instance to such a version, would remove this restriction on views completely.

However, if you have a current production MySQL version that is earlier than v5.7.7, then the removal of this restriction on views should only be one of the criteria being assessed while making a decision as to upgrade or not. Using the workaround techniques described in the other answers may be a more viable solution - at least on the shorter run.

Share:
129,244
Raouf Athar
Author by

Raouf Athar

Updated on July 13, 2022

Comments

  • Raouf Athar
    Raouf Athar almost 2 years

    I have two tables and I need to create a view. The tables are:

    credit_orders(id, client_id, number_of_credits, payment_status)
    credit_usage(id, client_id, credits_used, date)
    

    I use the following query to do this. The query without the "create view" part works well but with "create view", it shows the error "View's SELECT contains a subquery in the FROM clause". What could be the issue & possible solution:

    create view view_credit_status as 
    (select credit_orders.client_id, 
            sum(credit_orders.number_of_credits) as purchased, 
            ifnull(t1.credits_used,0) as used 
     from credit_orders
     left outer join (select * from (select credit_usage.client_id, 
                                            sum(credits_used) as credits_used 
                                     from credit_usage 
                                     group by credit_usage.client_id) as t0
                      ) as t1 on t1.client_id = credit_orders.client_id
     where credit_orders.payment_status='Paid'
     group by credit_orders.client_id)
    
  • miguelcobain
    miguelcobain over 11 years
    Note that nesting views can cause serious performance penalties.
  • Pacerier
    Pacerier about 9 years
    @miguelcobain, Creating a new view just to nest it doesn't remove the "serious performance penalties" you are talking about. So what gives?
  • François Breton
    François Breton about 8 years
    Now allowed in 5.7 ! :-)
  • peter
    peter over 5 years
    Not allowed in MariaDB either