What are the circumstances under which a finally {} block will NOT execute?

27,941

Solution 1

If you call System.exit() the program exits immediately without finally being called.

A JVM Crash e.g. Segmentation Fault, will also prevent finally being called. i.e. the JVM stops immediately at this point and produces a crash report.

An infinite loop would also prevent a finally being called.

The finally block is always called when a Throwable is thrown. Even if you call Thread.stop() which triggers a ThreadDeath to be thrown in the target thread. This can be caught (it's an Error) and the finally block will be called.


public static void main(String[] args) {
    testOutOfMemoryError();
    testThreadInterrupted();
    testThreadStop();
    testStackOverflow();
}

private static void testThreadStop() {
    try {
        try {
            final Thread thread = Thread.currentThread();
            new Thread(new Runnable() {
                @Override
                public void run() {
                    thread.stop();
                }
            }).start();
            while(true)
                Thread.sleep(1000);
        } finally {
            System.out.print("finally called after ");
        }
    } catch (Throwable t) {
        System.out.println(t);
    }
}

private static void testThreadInterrupted() {
    try {
        try {
            final Thread thread = Thread.currentThread();
            new Thread(new Runnable() {
                @Override
                public void run() {
                    thread.interrupt();
                }
            }).start();
            while(true)
                Thread.sleep(1000);
        } finally {
            System.out.print("finally called after ");
        }
    } catch (Throwable t) {
        System.out.println(t);
    }
}

private static void testOutOfMemoryError() {
    try {
        try {
            List<byte[]> bytes = new ArrayList<byte[]>();
            while(true)
                bytes.add(new byte[8*1024*1024]);
        } finally {
            System.out.print("finally called after ");
        }
    } catch (Throwable t) {
        System.out.println(t);
    }
}

private static void testStackOverflow() {
    try {
        try {
            testStackOverflow0();
        } finally {
            System.out.print("finally called after ");
        }
    } catch (Throwable t) {
        System.out.println(t);
    }
}

private static void testStackOverflow0() {
    testStackOverflow0();
}

prints

finally called after java.lang.OutOfMemoryError: Java heap space
finally called after java.lang.InterruptedException: sleep interrupted
finally called after java.lang.ThreadDeath
finally called after java.lang.StackOverflowError

Note: in each case the thread kept running, even after SO, OOME, Interrupted and Thread.stop()!

Solution 2

Infinite loop in the try block.

Corrupt RAM? Program no longer runs as written? I've actually debugged that once on a DOS machine.

Solution 3

Testing the finally block in different statement in try block.

 public static void main(String [] args){

    try{
        System.out.println("Before Statement");
        /*** Statement ***/
        System.out.println("After Statement");
    }
    catch(Exception e){
    }
    finally{
        System.out.println("Finally is Executed");
    }

Statements in which finally block is executed are following:

  1. Thread.currentThread().interrupted();
  2. Thread.currentThread().destroy();
  3. Thread.currentThread().stop();
  4. Thread.sleep(10);
  5. Thread.currentThread().interrupt();
  6. Runtime.getRuntime().addShutdownHook(Thread.currentThread());
  7. If there is any exception occurred.
  8. If there is no exception.

Statements in which finally block is not executed are following:

  1. Thread.currentThread().suspend();
  2. System.exit(0);
  3. JVM crashed.
  4. Power to CPU chip goes off.
  5. OS kills JVM process.
  6. Runtime.getRuntime().exit(0);
  7. Runtime.getRuntime().halt(0);

Solution 4

There is a chance of partial execution when finally itself throws an exception (or leads to an error)

Solution 5

One could be "A finally is a part of daeomon thread it may not be executed".

Share:
27,941
asteri
Author by

asteri

Updated on March 13, 2020

Comments

  • asteri
    asteri about 4 years

    In a Java try{} ... catch{} ... finally{} block, code within the finally{} is generally considered "guaranteed" to run regardless of what occurs in the try/catch. However, I know of at least two circumstances under which it will not execute:

    • If System.exit(0) is called; or,
    • if an Exception is thrown all the way up to the JVM and the default behavior occurs (i.e., printStackTrace() and exit)

    Are there any other program behaviors that will prevent the code in a finally{} block from executing? Under what specific conditions will the code execute or not?

    EDIT: As NullUserException pointed out, the second case is actually not true. I thought it was because the text in standard error printed after that in standard out, preventing the text from being seen without scrolling up. :) Apologies.