What is the difference between .Semaphore() and .BoundedSemaphore()?

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Solution 1

A Semaphore can be released more times than it's acquired, and that will raise its counter above the starting value. A BoundedSemaphore can't be raised above the starting value.

from threading import Semaphore, BoundedSemaphore

# Usually, you create a Semaphore that will allow a certain number of threads
# into a section of code. This one starts at 5.
s1 = Semaphore(5)

# When you want to enter the section of code, you acquire it first.
# That lowers it to 4. (Four more threads could enter this section.)
s1.acquire()

# Then you do whatever sensitive thing needed to be restricted to five threads.

# When you're finished, you release the semaphore, and it goes back to 5.
s1.release()


# That's all fine, but you can also release it without acquiring it first.
s1.release()

# The counter is now 6! That might make sense in some situations, but not in most.
print(s1._value)  # => 6

# If that doesn't make sense in your situation, use a BoundedSemaphore.

s2 = BoundedSemaphore(5)  # Start at 5.

s2.acquire()  # Lower to 4.

s2.release()  # Go back to 5.

try:
    s2.release()  # Try to raise to 6, above starting value.
except ValueError:
    print('As expected, it complained.')    

Solution 2

The threading module provides the simple Semaphore class.

A Semaphore provides a non-bounded counter which allows you to call release() any number of times for incrementing.

However, to avoid programming errors, it’s usually a correct choice to use BoundedSemaphore , which raises an error if a release() call tries to increase the counter beyond its maximum size.

EDIT

A semaphore has an internal counter rather than a lock flag (in case of Locks), and it only blocks if more than a given number of threads have attempted to hold the semaphore. Depending on how the semaphore is initialized, this allows multiple threads to access the same code section simultaneously.

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Benyamin Jafari - aGn
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Benyamin Jafari - aGn

⋆I've studied at NODET High School. ⋆B.Sc. in Software Engineering at QIAU University. ⋆M.Sc. in Mechatronic Engineering from QIAU University. ⋆I used to do R&D at Mechatronics Research Laboratory (MRL) in the @Home team. ⋆Python/Django Backend Developer at Arta Vision Ava – Data Center Infrastructure Management (IVMS | DCIM). ⋆Machine Learning and Robotics enthusiast, especially Deep Learning and Self-Driving Cars. Tokens of appreciation are very welcome if you've appreciated my assistance: ­⋆BTC Donations: bc1qw7x5yk7cmu2kg5wutalwf58z0mttcckj8w0av2 ⋆ETH Donations: 0xA892c4bd5509E2549f74A0f8405279CCDA4A69De ⋆TRX Donations: TJUngJzu2oRPqtT9KDtJAcBVepdJofsnbd ⋆TOMO Donations: 0xB2C87EF5243cF7aCD715B87c482E0c743B270a91

Updated on June 21, 2022

Comments

  • Benyamin Jafari - aGn
    Benyamin Jafari - aGn almost 2 years

    I know that threading.Lock() is equal to threading.Semaphore(1).

    Is also threading.Lock() equal to threading.BoundedSemaphore(1) ?

    And newly I saw threading.BoundedSemaphore(), what is the difference between them? For example in the following code snippet (applying limitation on threads):

    import threading
    
    sem = threading.Semaphore(5)
    sem = threading.BoundedSemaphore(5)