Which has more priority: || or && or ==

Question

I have this expression:

y[i] = ( z[i] == a && b || c )

Which of these elements (&&, ||, ==) have the priority?

Can you please show the order of operations with brackets?

Solution 1

First ==, then &&, then ||.

Your expression will be evaluated as y[i] = (((z[i] == a) && b) || c).

https://docs.oracle.com/javase/tutorial/java/nutsandbolts/operators.html

Solution 2

The priority list:

1. ==
   
2. &&
   
3. ||
   

Solution 3

The actual expression is evaluated as

y[i] = ( ((z[i] == a) && b) || c )

You probably want to look here for more info on operator precedence. https://docs.oracle.com/javase/tutorial/java/nutsandbolts/operators.html

Solution 4

This would be :

y[i] = ((( (z[i]) == a )&& b) || c)

ref: http://introcs.cs.princeton.edu/java/11precedence/

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Comments

[D. Ben Knoble]

Quick google search reveals the answer

[Gyuhyeon Lee]

fun fact is that this is now literally the highest google search for the query "java and or priority"