Why does my code print "built-in method" and some hex numbers?

Question

Here is my Key function:

def Key(message, decision):
    key = input("Input the key which will be used to encode the message.\n".lower)
    n = 0
    for i in range(len(key)):
        if 64 < ord(key[n]) < 91:
            raise ValueError(key[n], "is a capital letter!")
        else:
            n = n+1
    Keycode(decision, message, key)

When I call it and input the message and press enter it comes up with:

built-in method lower of str object at 0x0150E0D0

What's wrong? How can I fix it?

Solution 1

Key contains this problematic line:

key = input("Now, input the key which will be used to encode the message.\n".lower)

which passes as input to input the lower method of a string, when you (presumably) want to pass the string and then apply lower to what input returns.

Solution 2

After .upper or .lower there has to be a closed pair of parentheses. You can put custom arguments in them but if you just want to capitalize the input leave them empty.

Example:

user=(input("Enter a letter:")).upper()

This will change case to upper.

Solution 3

You need to use closed pair of parenthesis after lower

key = input("Input the key which will be used to encode the message.\n".lower())

Solution 4

key = input("Input the key which will be used to encode the message.\n".lower)

Because lower function is missing parenthesis, put parenthesis after function call. so syntax would be like key = input("Input the key which will be used to encode the message.\n".lower())

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Comments

[Sabrina Leggett]

this is what I get for using ruby for too long. I just spent 30 minutes trying to debug this.