Why does std::getline() skip input after a formatted extraction?
Solution 1
Why does this happen?
This has little to do with the input you provided yourself but rather with the default behavior std::getline()
has. When you provided your input for the age (std::cin >> age
), you not only submitted the following characters, but also an implicit newline was appended to the stream when you typed Enter:
"10\n"
A newline is always appended to your input when you select Enter or Return when submitting from a terminal. It is also used in files for moving toward the next line. The newline is left in the buffer after the extraction into age
until the next I/O operation where it is either discarded or read. When the flow of control reaches std::getline()
, it will see "\nMr. Whiskers"
and the newline at the beginning will be discarded, but the input operation will stop immediately. The reason this happens is because the job of std::getline()
is to attempt to read characters and stop when it finds a newline. So the rest of your input is left in the buffer unread.
Solution
cin.ignore()
To fix this, one option is to skip over the newline before doing std::getline()
. You can do this by calling std::cin.ignore()
after the first input operation. It will discard the next character (the newline character) so that it is no longer in the way.
std::cin >> age;
std::cin.ignore();
std::getline(std::cin, name);
assert(std::cin);
// Success!
std::ws
Another way to discard the whitespace is to use the std::ws
function which is a manipulator designed to extract and discard leading whitespace from the beginning of an input stream:
std::cin >> age;
std::getline(std::cin >> std::ws, name);
assert(std::cin);
// Success!
The std::cin >> std::ws
expression is executed before the std::getline()
call (and after the std::cin >> age
call) so that the newline character is removed.
The difference is that ignore()
discards only 1 character (or N characters when given a parameter), and std::ws
continues to ignore whitespace until it finds a non-whitespace character. So if you don't know how much whitespace will precede the next token you should consider using this.
Match the operations
When you run into an issue like this it's usually because you're combining formatted input operations with unformatted input operations. A formatted input operation is when you take input and format it for a certain type. That's what operator>>()
is for. Unformatted input operations are anything other than that, like std::getline()
, std::cin.read()
, std::cin.get()
, etc. Those functions don't care about the format of the input and only process raw text.
If you stick to using a single type of formatting then you can avoid this annoying issue:
// Unformatted I/O
std::string age, name;
std::getline(std::cin, age);
std::getline(std::cin, name);
or
// Formatted I/O
int age;
std::string firstName, lastName;
std::cin >> age >> firstName >> lastName;
If you choose to read everything as strings using the unformatted operations you can convert them into the appropriate types afterwards.
Solution 2
Everything will be OK if you change your initial code in the following way:
if ((cin >> name).get() && std::getline(cin, state))
Solution 3
This happens because an implicit line feed also known as newline character \n
is appended to all user input from a terminal as it's telling the stream to start a new line. You can safely account for this by using std::getline
when checking for multiple lines of user input. The default behavior of std::getline
will read everything up to and including the newline character \n
from the input stream object which is std::cin
in this case.
#include <iostream>
#include <string>
int main()
{
std::string name;
std::string state;
if (std::getline(std::cin, name) && std::getline(std::cin, state))
{
std::cout << "Your name is " << name << " and you live in " << state;
}
return 0;
}
Input: "John" "New Hampshire" Output: "Your name is John and you live in New Hampshire"
Solution 4
Since everyone above has answered the problem for input 10\nMr Whisker\n
, I would like to answer a different approach. all the solution above published the code for if the buffer is like 10\nMr Whisker\n
. but what if we don't know how user will behave giving input. the user might type 10\n\nMr. Whisker\n
or 10 \n\n Mr. whisker\n
by mistake. in that case, codes above may not work. so, I use the function below to take string input to address the problem.
string StringInput() //returns null-terminated string
{
string input;
getline(cin, input);
while(input.length()==0)//keep taking input until valid string is taken
{
getline(cin, input);
}
return input.c_str();
}
So, the answer would be:
#include <iostream>
#include <string>
int main()
{
int age;
std::string name;
std::cin >> age;
name = StringInput();
std::cout << "My cat is " << age << " years old and their name is " << name << std::endl;
}
Extra:
If user inputs a \n10\n \nmr. whiskey
;
To check whether int
input is valid or not, this function can be used to check int
input (program will have undefined behavior if char
is given as input instead of int
):
//instead of "std::cin>>age;" use "get_untill_int(&age);" in main function.
void get_Untill_Int(int* pInput)//keep taking input untill input is `int or float`
{
cin>> *pInput;
/*-----------check input validation----------------*/
while (!cin)
{
cin.clear();
cin.ignore(100, '\n');
cout<<"Invalid Input Type.\nEnter again: ";
cin >>*pInput;
}
/*-----------checked input validation-------------*/
}
Solution 5
I am really wondering. C++ has a dedicated function for eating up any remaining or whatever white spaces. It is called std::ws. And then, you can simply use
std::getline(std::cin >> std::ws, name);
That should be the idomatic approach. For each transistion between formatted to unformatted input that should be used.
If we are not talking about white spaces, but entering for example letters where a number is expected, then we should follow the CPP reference and use
.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
to eliminate the wrong stuff.
Please read here
Comments
-
David G over 2 years
I have the following piece of code that prompts the user for their cat's age and name:
#include <iostream> #include <string> int main() { int age; std::string name; std::cin >> age; std::getline(std::cin, name); if (std::cin) { std::cout << "My cat is " << age << " years old and their name is " << name << std::endl; } }
What I find is that the age has been successfully read, but not the name. Here is the input and output:
Input: "10" "Mr. Whiskers" Output: "My cat is 10 years old and their name is "
Why has the name been omitted from the output? I've given the proper input, but the code somehow ignores it. Why does this happen?
-
David G about 10 yearsThank you. This will also work because
get()
consumes the next character. There's also(std::cin >> name).ignore()
which I suggested earlier in my answer. -
Boris about 10 years"..work because get()..." Yes, exactly. Sorry for giving the answer without details.
-
Drew Delano over 7 yearsWhy not simply
if (getline(std::cin, name) && getline(std::cin, state))
? -
Drew Delano over 7 yearsWhy not simply
if (getline(std::cin, name) && getline(std::cin, state))
? -
David G over 7 years@FredLarson Good point. Though it wouldn't work if the first extraction is of an integer or anything that isn't a string.
-
Drew Delano over 7 yearsOf course, that isn't the case here and there's no point in doing the same thing two different ways. For an integer you could get the line into a string and then use
std::stoi()
, but then it's not so clear there's an advantage. But I tend to prefer to just usestd::getline()
for line-oriented input and then deal with parsing the line in whatever way makes sense. I think it's less error prone. -
David G over 7 years@FredLarson Agreed. Maybe I'll add that in if I have the time.
-
Albin about 4 yearsSo what if I had a program that first inputs a number X and then runs a loop that inputs strings X number of times - how would I go about it? Should I write the first iteration code outside the loop with a cin.ignore() and then run the loop X-1 times?
-
David G about 4 years@Albin The reason you might want to use
std::getline()
is if you want to capture all characters up to a given delimiter and input it into a string, by default that is the newline. If thoseX
number of strings are just single words/tokens then this job can be easily accomplished with>>
. Otherwise you would input the first number into an integer with>>
, callcin.ignore()
on the next line, and then run a loop where you usegetline()
. -
Armin Montigny over 2 yearsUnbelievable. So many upvotes. Nobody heard of
std::ws
? Why not simply writingstd::getline(std::cin>>std::ws, name);
? What is going on here? -
David G over 2 years@armin That used to be in my answer before I made a major edit for simplicity. I'll put it back in.
-
kNIG132103 over 2 yearsthnks you so much.