Why is this prolog query both true and false?

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Solution 1

(Note: this answer is somewhat of a guess)

Consider how Prolog determines whether f(a,c) is true or not. It checks the first rule, f(a,b), and doesn't find a match, but the second rule, f(a,c) matches. Therefore, f(a,c) is true. Furthermore, since there are no more rules for f, there is no point in allowing a backtrack to occur -- there are no other possible solutions.

Now consider f(a,b). Prolog will check the first rule, and find a match. Therefore, f(a,b) is true. However, not all rules have been exhausted. Therefore, Prolog will allow the search to continue (if you hit ;). When you do continue the search and backtrack, it will discover that the remaining rules, specifically f(a,c), do not match f(a,b). Therefore, the result is false.

Solution 2

Just in addition to Michael Williamson's answer. If you want to tell Prolog to stop looking for answers after the first successful hit, then use the cut (!):

?- f(a, b), !.
true.

?- f(a, c), !.
true.
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Updated on June 03, 2022

Comments

  • Admin
    Admin almost 2 years

    My SWI-Prolog knowledge base contains the following two facts:

    f(a,b).
    f(a,c).
    

    Now if I pose the query

    ?- f(a,c).
    true.
    

    But

    ?- f(a,b).
    true ;
    false.
    

    Why is f(a,b) both true and false? This also happens when there are three facts in the KB. If I append f(a,d). to the KB, then f(a,d) is true (only), but f(a,b) and f(a,c) are both true and false. What's going on, and what can I do so that Prolog answers (only) true to these queries?