Why j_spring_security_check 404?

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I think it may be the fact your security form should point to

/master/j_spring_security_check
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xwhyz
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xwhyz

Updated on June 27, 2022

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  • xwhyz
    xwhyz almost 2 years

    I'm trying to implement form based authentication with Spring security. Redirection works fine: my main page works correctly and for http://localhost:8080/master/admin I'm redirected to login page (http://localhost:8080/master/login/):

        <form action="j_spring_security_check" method="POST">
            <label for="username">User Name:</label>
            <input id="username" name="j_username" type="text"/>
            <label for="password">Password:</label>
            <input id="password" name="j_password" type="password"/>
            <input type="submit" value="Log In"/>
          </form>
    
    but when I submit I get 404 on address: `http://localhost:8080/master/login/j_spring_security_check`
    

    Here's my configuration web.xml:

        <context-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/spring/root-context.xml</param-value>
        </context-param>
        <filter>
            <filter-name>springSecurityFilterChain</filter-name>
            <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
        </filter>
        <filter-mapping>
            <filter-name>springSecurityFilterChain</filter-name>
            <url-pattern>/*</url-pattern>
        </filter-mapping>
    
        <!-- Creates the Spring Container shared by all Servlets and Filters -->
        <listener>
            <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
        </listener>
    
        <!-- Processes application requests -->
        <servlet>
            <servlet-name>appServlet</servlet-name>
            <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
            <init-param>
                <param-name>contextConfigLocation</param-name>
                <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
            </init-param>
            <load-on-startup>1</load-on-startup>
        </servlet>
        <servlet-mapping>
            <servlet-name>appServlet</servlet-name>
            <url-pattern>/</url-pattern>
        </servlet-mapping>
    

    And my root-context.xml (i made redirection to google so that I know page exists in context)

    <sec:http auto-config="true">
        <sec:intercept-url pattern="/admin/**" access="ROLE_USER" />
        <sec:form-login login-page="/login/"
            authentication-failure-url="http://www.google.com" default-target-url="http://www.google.com" />
        <sec:logout logout-success-url="/logout" />
    </sec:http>
    
    <sec:authentication-manager>
        <sec:authentication-provider>
            <sec:user-service>
                <sec:user name="test" password="test" authorities="ROLE_USER, ROLE_ADMIN" />
                <sec:user name="testuser" password="testuserpassword"
                    authorities="ROLE_USER" />
            </sec:user-service>
        </sec:authentication-provider>
    </sec:authentication-manager> 
    

    I've lost quite a lot of time already, trying different combinations but no luck. Any help is appreciated!

  • Joshua Moore
    Joshua Moore over 10 years
    Here is some further information that will allow you better understand how and why: stackoverflow.com/questions/15365477/…