XElement namespaces (How to?)
63,030
Solution 1
It's really easy in LINQ to XML:
XNamespace ns = "sphinx";
XElement element = new XElement(ns + "docset");
Or to make the "alias" work properly to make it look like your examples, something like this:
XNamespace ns = "http://url/for/sphinx";
XElement element = new XElement("container",
new XAttribute(XNamespace.Xmlns + "sphinx", ns),
new XElement(ns + "docset",
new XElement(ns + "schema"),
new XElement(ns + "field", new XAttribute("name", "subject")),
new XElement(ns + "field", new XAttribute("name", "content")),
new XElement(ns + "attr",
new XAttribute("name", "published"),
new XAttribute("type", "timestamp"))));
That produces:
<container xmlns:sphinx="http://url/for/sphinx">
<sphinx:docset>
<sphinx:schema />
<sphinx:field name="subject" />
<sphinx:field name="content" />
<sphinx:attr name="published" type="timestamp" />
</sphinx:docset>
</container>
Solution 2
You can read the namespace of your document and use it in queries like this:
XDocument xml = XDocument.Load(address);
XNamespace ns = xml.Root.Name.Namespace;
foreach (XElement el in xml.Descendants(ns + "whateverYourElementNameIs"))
//do stuff
Author by
Edward83
Updated on May 08, 2020Comments
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Edward83 almost 4 years
How to create xml document with node prefix like:
<sphinx:docset> <sphinx:schema> <sphinx:field name="subject"/> <sphinx:field name="content"/> <sphinx:attr name="published" type="timestamp"/> </sphinx:schema>
When I try to run something like
new XElement("sphinx:docset")
i getting exceptionUnhandled Exception: System.Xml.XmlException: The ':' character, hexadecimal val ue 0x3A, cannot be included in a name.
at System.Xml.XmlConvert.VerifyNCName(String name, ExceptionType exceptionTyp e)
at System.Xml.Linq.XName..ctor(XNamespace ns, String localName)
at System.Xml.Linq.XNamespace.GetName(String localName)
at System.Xml.Linq.XName.Get(String expandedName) -
Edward83 about 13 yearsthank you, but for first version I got <docset xmlns="sphinx" /> it is not what I want;)))
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Jon Skeet about 13 years@Edward83: See my other example. Basically you'll need the namespace to be specified in xmlns somewhere...
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micahhoover almost 11 yearsAfter all the ugly hacks I've used to do this (recursive static methods to attach namespace to everything) ... I tried this approach first, but I didn't prefix XNamespace.Xmlns to the outer namespace. Why is that prefix even necessary? Does it set it for global?
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Jon Skeet almost 11 years@micahhoover: You should read the W3C namespacing specification. It's not entirely clear to me what you were trying to achieve, or what went wrong.
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deniz almost 9 yearsNice approach (+1)! However, this didn't work for me in a case where the root XML element had multiple xmlns attributes, i.e.: xmlns:soapenv="..." xmlns="...". Using xml.Root.GetDefaultNamespace() did get me what I wanted, which was the value of the plain xmlns="..." attribute.