Xpath: select node based in a condition (with local-name())

Question

The question is quite silly, but I am completely stuck. I want to extract child nodes of a node based on a condition. The XML is as follows:

<a> 
 <aCode>aaa</aCode>
 <aValue>bbb</aValue>
</a>

The expression is obvious: //a[aCode='aaa']

But I can't get how I should change it if it is with namespaces and I've got to use local-name(). I've tested the following and it gives a parsing error:

/*[local-name()='a'][[local-name()='aCode']='aaa']

Has anyone any idea of what I should do?

Solution 1

You probably meant

//*[local-name()='a'][*[local-name()='aCode']='aaa']

Solution 2

Try this

/a/aCode[text()='aaa']

or

//*[local-name() = 'aCode' and text() = 'aaa']

You have used // at wrong place.

Solution 3

This one work:

//*[local-name()='a'][*[local-name()='acode' and text()='a2']]

and also this one:

//*[local-name()='a'][aCode[text()='a2']]

Comments

[gisly]

Thanks! I just wanted to get both children.

[Arup Rakshit]

Here what * means - [*[local-name()='aCode']='aaa'] ? Help me to understand please!

[choroba]

* stands for "any element".