Zend Framework Select Objects And UNION()

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Solution 1

Zend_Db_Select has a union method so I'd have thought it is possible, if you can build your query using a select object. I haven't used Zend_Db_Select (or the table subclass) with union but I'd imagine you can do something like

$select = $this->select()
               ->where('blah')
               ->union($sql);

Solution 2

Here's what I've done to make a union:

$select = $this->select();
//common select from both sides of the union goes here

$select1 = clone($select);
//select1 specifics here

$select2 = clone($select);
//select 2 specifics here

$db = $this->getAdapter();
$pageselect = $db->select()->union(array("($select1)", "($select2)"));

Remember Db_Select's __toString will print out the SQL generated by that select, to help you debug.

Solution 3

a complete example:

 public function getReservationById($id)
 {
  if(!$id) return null;

  $sql = $this->table->select();
  $sql->union(array(
   $this->table->select()->where('id=?', $id),
   $this->tableFinished->select()->where('id=?', $id),
   $this->tableCanceled->select()->where('id=?', $id),
   $this->tableTrashed->select()->where('id=?', $id)
   ));
  echo $sql->__toString();
 }

and the generated query:

SELECT reservations.* FROM reservations WHERE (id='5658') UNION SELECT res_finished.* FROM res_finished WHERE (id='5658') UNION SELECT res_cancel.* FROM res_cancel WHERE (id='5658') UNION SELECT res_trash.* FROM res_trash WHERE (id='5658')

Solution 4

This practical example shows a function that returns a rowset of either latest or if a available favourite blog entries of a specific year (artwork blog):

public function fetchBestOf($year)
{
    $selectLatest = $this->select()->where('isHidden = 0')
                                   ->where('YEAR(dateCreated) = ' . $year)
                                   ->where('isHighlight = 0');
    $selectHighlights = $this->select()->where('isHidden = 0')
                                       ->where('YEAR(dateCreated) = ' . $year)
                                       ->where('isHighlight = 1');

    $selectUnion = $this->select()->union(array($selectLatest, $selectHighlights), Zend_Db_Select::SQL_UNION_ALL)
                   ->order('isHighlight DESC')
                   ->order('dateCreated DESC')
                   ->order('workID DESC')
                   ->limit('5');

    $rowset = $this->fetchAll($selectUnion);
    return $rowset;
}

Solution 5

The best way Zend suggest is like follows....

$sql = $this->_db->select()
    ->union(array($select1, $select2,$select3))
            ->order('by_someorder');

echo $sql->__toString();

$stmt = $db->query($sql);
$result = $stmt->fetchAll();

echo will show the query

Here $select1, $select2, $select3 can be different select queries with same number of columns...

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Richard Knop
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Richard Knop

I'm a software engineer mostly working on backend from 2011. I have used various languages but has been mostly been writing Go code since 2014. In addition, I have been involved in lot of infra work and have experience with various public cloud platforms, Kubernetes, Terraform etc. For databases I have used lot of Postgres and MySQL but also Redis and other key value or document databases. Check some of my open source projects: https://github.com/RichardKnop/machinery https://github.com/RichardKnop/go-oauth2-server https://github.com/RichardKnop

Updated on June 04, 2022

Comments

  • Richard Knop
    Richard Knop almost 2 years

    I'm pretty sure this is not possible in Zend Framework (I have searched the Web, the documentation and issue tracker) but I just want to make sure so I'm asking here.

    $select = $this->select();
    $select->union($select1, $select2);
    

    That doesn't work of course. To explain what I need. I need to use UNION() to merge 2 tables in a SELECT query, I know I could just do:

    $select = "$select1 UNION $select2";
    

    The problem is that would return a string and I need to get a select object so I can use it with Zend_Paginator.

    I have already solved the issue by modifying my database architecture but I'm just curious if there is some workaround for this.