Behavior of cd/bash on symbolic links

10,923

Solution 1

According to help cd,

  Options:
      -L        force symbolic links to be followed: resolve symbolic
                links in DIR after processing instances of `..'
      -P        use the physical directory structure without following
                symbolic links: resolve symbolic links in DIR before
                processing instances of `..'

In other words, -L means using the logical structure, whereas -P uses the actually physical directory structure.

The logical structure is like this,

$ tree a
a
└── b
    └── symlink -> ..

The actual physical structure when you go to a/b/symlink is,

a

If you want to use the real .., then you must also use cd -P:

          The -P option says to use the physical directory
          structure instead of following symbolic links (see
          also the -P option to the set builtin command);
          the -L option forces symbolic links to be followed.

An example,

$ cd
$ cd a/b/symlink   # physical location is at a/
$ cd ..            # now is at a/b
$ cd symlink       # goes back to a/b/symlink
$ cd -P ..         # follow physical path (resolve all symlinks)
$ pwd -P           # -P is optional here to show effect of cd ..
/home/sarnold
$ 

Solution 2

bash keeps track of the logical current directory path, as shown in your prompt, and interprets things like cd .. according to that. This makes things a little more consistent if you only use such paths in cd (or pushd), at the cost of unexpected things happening if you then expect the same thing to happen with paths in command arguments (or inside commands; emacs and vim have their own configurable rules for symlink handling, but most commands rely on the kernel to deal with it).

Share:
10,923
Hermann Speiche
Author by

Hermann Speiche

Updated on June 13, 2022

Comments

  • Hermann Speiche
    Hermann Speiche almost 2 years

    Assume I have the folders ~/a/b in my home folder, and the folder b contains a symbolic link to '..' named 'symlink'. Then I perform the following actions in bash:

    hm@mach:~$ cd a/b/symlink
    hm@mach:~/a/b/symlink$ pwd -P
    /home/hm/a
    hm@mach:~/a/b/symlink$ cd ..
    hm@mach:~/a/b$ pwd -P
    /home/hm/a/b
    

    pwd -P prints the current working directory, dereferencing all symbolic links. Why is the working directory /home/hm/a/b at the end, and not /home/hm?