C *char pointer to char array
14,237
Solution 1
The size of a
is 10
, so is the length of b
(including the null terminator). Change
for(i = 0; i < 9; i++)
to
for(i = 0; i < 10; i++)
Solution 2
What you are doing is right.
Juts change i<10
in your for loop.
There are 10 elements in your char array and the array index is from 0-9
.
Author by
user2959923
Updated on June 04, 2022Comments
-
user2959923 about 2 years
I have a *char pointer and a char array. How can I put the value of the pointer in the char array? I've tried
uint8_t i; char a[10]; char *b = "abcdefghi"; for(i = 0; i < 9; i++) { a[i] = b[i]; } printf("%s", a);
But this doesn't work.