C++ Constant structure member initialization
Solution 1
In C++11, you can initalise an aggregate member in the constructor's initialiser list:
Foo() : bar{1,1} {}
In older versions of the language, you would need a factory function:
Foo() : bar(make_bar()) {}
static timespec make_bar() {timespec bar = {1,1}; return bar;}
Solution 2
Use an initialization list with a helper function:
#include <iostream>
#include <time.h>
#include <stdexcept>
class Foo
{
private:
const timespec bar;
public:
Foo ( void ) : bar ( build_a_timespec() )
{
}
timespec build_a_timespec() {
timespec t;
if(clock_gettime(CLOCK_REALTIME, &t)) {
throw std::runtime_error("clock_gettime");
}
return t;
}
};
int main() {
Foo foo;
return 0;
}
Solution 3
Use initialization list
class Foo
{
private:
const timespec bar;
public:
Foo ( void ) :
bar(100)
{
}
};
If you want to initialize structure with bracers then use them
Foo ( void ) : bar({1, 2})
Comments
-
Kolyunya almost 2 years
I've a constant
struct timespec
member in my class. How am I supposed to initialize it?The only crazy idea I got is to derive my own
timespec
and give it a constructor.Thanks much!
#include <iostream> class Foo { private: const timespec bar; public: Foo ( void ) : bar ( 1 , 1 ) { } }; int main() { Foo foo; return 0; }
Compilation finished with errors: source.cpp: In constructor 'Foo::Foo()': source.cpp:9:36: error: no matching function for call to 'timespec::timespec(int, int)' source.cpp:9:36: note: candidates are: In file included from sched.h:34:0, from pthread.h:25, from /usr/lib/gcc/i686-pc-linux-gnu/4.7.2/../../../../include/c++/4.7.2/i686-pc-linux-gnu/bits/gthr-default.h:41, from /usr/lib/gcc/i686-pc-linux-gnu/4.7.2/../../../../include/c++/4.7.2/i686-pc-linux-gnu/bits/gthr.h:150, from /usr/lib/gcc/i686-pc-linux-gnu/4.7.2/../../../../include/c++/4.7.2/ext/atomicity.h:34, from /usr/lib/gcc/i686-pc-linux-gnu/4.7.2/../../../../include/c++/4.7.2/bits/ios_base.h:41, from /usr/lib/gcc/i686-pc-linux-gnu/4.7.2/../../../../include/c++/4.7.2/ios:43, from /usr/lib/gcc/i686-pc-linux-gnu/4.7.2/../../../../include/c++/4.7.2/ostream:40, from /usr/lib/gcc/i686-pc-linux-gnu/4.7.2/../../../../include/c++/4.7.2/iostream:40, from source.cpp:1: time.h:120:8: note: timespec::timespec() time.h:120:8: note: candidate expects 0 arguments, 2 provided time.h:120:8: note: constexpr timespec::timespec(const timespec&) time.h:120:8: note: candidate expects 1 argument, 2 provided time.h:120:8: note: constexpr timespec::timespec(timespec&&) time.h:120:8: note: candidate expects 1 argument, 2 provided
-
matth over 11 yearsIt might be worth noting that the brace initializer is a C++11 feature.
-
David Rodríguez - dribeas over 11 yearsI would make that a
static
(internal linkage) function or even a lambda in C++11 to avoid polluting the class interface. -
matth over 11 years@DavidRodríguez-dribeas - Good thought. I'd have made it a private member function if I had been thinking about it. I'd make it a
static
free function only if the initialization is generally unrelated to the class functionality. -
Kolyunya over 11 yearsMike, could you please tell me or throw a good link about how do I use this syntax. Since
bar{1,1} {}
,bar{1,1}
andbar({1,1})
work correctly. What is the correct syntax? -
Mike Seymour over 11 years@Kolyunya:
bar{1,1}
andbar({1,1})
are both correct; the first specifies list-initialisation, while the second specifies direct-initialisation from an initialiser list, which does the same thing. I'd use the first because it's less squiggly, and says more clearly what I want to do.