C++ popen()'s output to a string
Solution 1
I suppose I'd do something on this general order:
char big_buffer[BIG_SIZE];
char small_buffer[LINE_SIZE];
unsigned used = 0;
big_buffer[0] = '\0'; // initialize the big buffer to an empty string
// read a line data from the child program
while (fgets(small_buffer, LINE_SIZE, your_pipe)) {
// check that it'll fit:
size_t len = strlen(small_buffer);
if (used + len >= BIG_SIZE)
break;
// and add it to the big buffer if it fits
strcat(big_buffer, small_buffer);
used += strlen(small_buffer);
}
If you want to get more elaborate, you could allocate space dynamically, and attempt to increase it as necessary to hold the amount of output you get. That would be a better route unless you have at least some idea of how much output the child might produce.
Edit: Given that you're using C++, a result with dynamic size is actually pretty easy:
char line[line_size];
std::string result;
while (fgets(line, line_size, your_pipe))
result += line;
Solution 2
Read the output from the FILE*
into a string using the usual stdio
routines.
Solution 3
See https://stackoverflow.com/a/10702464/981959
You can do it in two lines (three including a typedef to improve readability):
#include <pstream.h>
#include <string>
#include <iterator>
int main()
{
redi::ipstream proc("./some_command");
typedef std::istreambuf_iterator<char> iter;
std::string output(iter(proc.rdbuf()), iter());
}
This takes care of all memory allocation and closing the stream again when you're finished with it.
Tabrez Ahmed
Updated on June 23, 2022Comments
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Tabrez Ahmed almost 2 years
C++'s
popen()
returns a file descriptor that contains the output, after executing a process. Instead of a FILE*, I need a char*, ie. a string to be my output. What do I do? Please help me.