CakePHP - How to return string (like JSON) from controller action to Ajax request
Solution 1
do this, have your variables you want to output in an array let's say $data
, then pass that array to the view using the $this->set('data', $data);
method, then create a view /General/SerializeJson.ctp
. In that view file, put <?PHP echo json_encode($data); ?>
after that you can use $this->render('/General/SerializeJson');
and it should output the json.
General code...
/Controllers/MyController.php
public class MyController extends AppController
{
public function ajaxAction()
{
$data = Array(
"name" => "Saad Imran",
"age" => 19
);
$this->set('data', $data);
$this->render('/General/SerializeJson/');
}
}
/Views/General/SerializeJson.ctp
<?PHP echo json_encode($data); ?>
Solution 2
Easiest way I found was to disable the automatic rendering:
function ajax_action($data = null) {
if($this->RequestHandler->isAjax()) {
$this->autoRender = false;
//process my data and return it
return $data;
} else {
$this->Session->setFlash(__('Not an AJAX Query', true));
$this->redirect(array('action' => 'index'));
}
}
Solution 3
try this:
within your view
folder for the corresponding controller
(my_controller) make a folder named json
and place a file named index.ctp
and within that ctp file write this code:
<?php echo json_encode($yourVariableNameReturnedFromController); ?>
within your my_controller
in index()
wrote this code:
$this->set('yourVariableNameReturnedFromController', $this->YOURMODEL->find('all'));
within your app_controller.php
(if not exist you have to made it) write this code
function beforeFilter(){
if ($this->RequestHandler->ext == 'json') {
Configure::write('debug', 0);
}
}
Solution 4
AutoRender=false and Return json_encode($code)
public function returningJsonData($estado_id){
$this->autoRender = false;
return json_encode($this->ModelBla->find('first',array(
'conditions'=>array('Bla.bla_child_id'=>$estado_id)
)));
}
BadHorsie
Updated on July 10, 2022Comments
-
BadHorsie almost 2 years
So I have my JavaScript making an Ajax call to
/my_controller/ajax_action
but then in the controller I don't know what to do to output something back to the JavaScript.I am getting errors because there is no view for
MyController::ajaxAction()
but obviously there is no view for it, so what do I do? -
thecodeparadox over 12 yearshere i use
index()
function for accessing the json and your url will like '/my_controller/index.json'