Can I call pushd/popd and prevent it printing the stack?

Question

After calling pushd/popd in bash, it will print off the current directory stack. Is there any way to prevent this behaviour, so that it will act 'quitely'? This sort of noise in a command is uncommon in unix tools.

Solution

I think this sort of "noise" is not uncommon, that's why you often do this:

pushd > /dev/null

Comments

[violet]

You can also make a function to basically redefine the command and stick it in .bashrc such as: pushd() { builtin pushd $1 > /dev/null; }

[Araejay]

Good tip, but most unix tools don't print to the terminal EVERY TIME, but only if there's an error

[vidstige]

I'd say its uncommon. The linux philosophy is actually to not print anything if everything went well except the output of the program or builtin if any. For example cd, ls, aso.

[Shital Shah]

Some people do pushd &> /dev/null. I'd say don't do that because & means redirect both stdout and stderr. Normally you only want to redirect stdout.