I would like to store all command-line arguments to a Bash script into a single variable
Solution 1
echo "$*"
would do what you want, namely printing out the entire command-line arguments, separated by a space (or, technically, whatever the value of $IFS
is). If you wanted to store it into a variable, you could do
thevar="$*"
If that doesn't answer your question well enough, I'm not sure what else to say...
Solution 2
If you want to avoid having $IFS involved, use $@ (or don't enclose $* in quotes)
$ cat atsplat
IFS="_"
echo " at: $@"
echo " splat: $*"
echo "noquote: "$*
$ ./atsplat this is a test
at: this is a test
splat: this_is_a_test
noquote: this is a test
The IFS behavior follows variable assignments, too.
$ cat atsplat2
IFS="_"
atvar=$@
splatvar=$*
echo " at: $atvar"
echo " splat: $splatvar"
echo "noquote: "$splatvar
$ ./atsplat2 this is a test
at: this is a test
splat: this_is_a_test
noquote: this is a test
Note that if the assignment to $IFS were made after the assignment of $splatvar, then all the outputs would be the same ($IFS would have no effect in the "atsplat2" example).
Mark Biek
Updated on August 21, 2020Comments
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Mark Biek almost 4 years
Let's say I have a Bash script called foo.sh.
I'd like to call it like this:
foo.sh Here is a bunch of stuff on the command-line
And I'd like it to store all of that text into a single variable and print it out.
So my output would be:
Here is a bunch of stuff on the command-line
How would I do this?