Can I pass multiple values in the <option> tag?
Solution 1
You cannot have Multiple values in an Option Tag.
If the Name of the Front and Back-Image only differ by the Page-number, you can use this code:
function selectFlyer(name){
selectFront(name+"pag1.png");
selectBack(name+"pag2.png");
}
function selectFront(imgSrc) {
loadImage(imgSrc);
var Dim_Slice = document.querySelectorAll(".slice");
for (var i = 0; i < Dim_Slice.length; i++) {
Dim_Slice[i].style.backgroundImage = "url(" + imgSrc + ")";
}
}
function selectBack(imgSrc) {
loadImage(imgSrc);
var Dim_Sliceb = document.querySelectorAll(".sliceb");
for (var i = 0; i < Dim_Sliceb.length; i++) {
Dim_Sliceb[i].style.backgroundImage = "url(" + imgSrc + ")";
}
}
<form name="Pictures">
<select name="dropPic" onchange="selectFlyer(this.value)">
<option value="Flyer1">Flyer 1</option>
<option value="Flyer2">Flyer 2</option>
<option value="Flyer3">Flyer 3</option>
</select>
</form>
Solution 2
it can be done in this way
<select id="dropPic">
<option data-picone="Flyer1pag1.png" data-pictwo="Flyer1pag2.png">Flyer 1</option>
<option data-picone="Flyer2pag1.png" data-pictwo="Flyer1pag2.png">Flyer 2</option>
<option data-picone="Flyer3pag1.png" data-pictwo="Flyer1pag2.png">Flyer 3</option>
</select>
And on change event you can get the value as below
$("#dropPic").change(function () {
alert($(this).find(':selected').data('picone'));
});
Check this link for similar question
Can an Option in a Select tag carry multiple values?
Solution 3
Your question and / or what you're trying to do isn't entirely clear, but I think this is what you want:
<form name="Pictures">
<select name="dropPic"
onchange="selectFront(this.value.split(',')[0]);selectBack(this.value.split(',')[1]);">
<option value="Flyer1pag1.png,Flyer1pag2.png">Flyer 1</option>
<option value="Flyer2pag1.png,Flyer1pag2.png">Flyer 2</option>
<option value="Flyer3pag1.png,Flyer1pag2.png">Flyer 3</option>
</select>
</form>
Pikachuu
I only use this site to search for work-related questions.
Updated on August 25, 2021Comments
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Pikachuu over 2 years
I have a program that simulates a folding effect on a flyer that has a front image and a back image. I select the flyers through a dropDownList. How can I pass the back image in the tag so that, when I rotate the image, the picture on the back is shown?
This is the HTML for my dropDownList:
<form name="Pictures"> <select name="dropPic" onchange="selectFront(this.value)"> <option value="Flyer1pag1.png" value="Flyer1pag2.png">Flyer 1</option> <option value="Flyer2pag1.png" value="Flyer1pag2.png">Flyer 2</option> <option value="Flyer3pag1.png" value="Flyer1pag2.png">Flyer 3</option> </select> </form>
Here is the function in JavaScript that changes the front image regarding the selection of the dropDownList and the function that should take the back image of the flyer:
function selectFront(imgSrc) { loadImage(imgSrc); var Dim_Slice = document.querySelectorAll(".slice"); for (var i = 0; i < Dim_Slice.length; i++) { Dim_Slice[i].style.backgroundImage = "url(" + imgSrc + ")"; } } function selectBack(imgSrc) { var Dim_Sliceb = document.querySelectorAll(".sliceb"); for (var i = 0; i < Dim_Sliceb.length; i++) { Dim_Sliceb[i].style.backgroundImage = "url(" + imgSrc + ")"; } }
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Lelio Faieta almost 9 yearsYou can use data attributes to store as many other values as you want. Data attributes are there for exactly this kind of needs. You are starting from. Wrong assumption
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Pikachuu almost 9 years@TorbenH. That is very good idea. I would never think of that. Thank you! :)
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Simon.S.A. about 5 yearsWelcome to stackoverflow. You need to explain your answer - just posting code does not provide a high quality answer.