Can you set style in d3 via something like foo.style({color:blah, background:blah})?

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Solution 1

Only works on D3 v3:
To quote the documentation:

If you want to set several style properties at once, use an object literal like so:

selection.style({'stroke': 'black', 'stroke-width': 2})

This isn't possible with functions though, so in your case you still have to use the "long form".

Solution 2

You can specify a separate function for each style name in the style literal, like so:

d3.selectAll(".whatever").style({
    color: function(d) { return getColor(d); },
    background: function(d) { return getBackground(d); }
});

Solution 3

The easiest way of applying multiple css (static or dynamic) in d3 is to set style as many times as you need it. For example:

d3.selectAll('whatever') .style('color', 'green') .style('height', (d) => d + 'px');

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user655489
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Updated on June 13, 2022

Comments

  • user655489
    user655489 almost 2 years

    I am going to set various css styles on an svg element, and was thinking I could do something like

    d3.selectAll(".whatever")
       .style(function(d) { return {"color":getColor(d), "background":getBackground(d)}});
    

    Now, this doesn't work, but I'm wondering if I can do something similar to centralize setting overall style properties rather than set style properties individually.

    Note: as Ray suggested, you can do something like this (I'm assuming you've already got data attached to the nodes):

    d3.selectAll(".whatever")
      .attr("style",function(d) {
         return cssStyleStringYouWantToUse(d);
      });