Cannot implicitly convert type 'int' to 'short'
Solution 1
Microsoft converts your Int16
variables into Int32
when doing the add function.
Change the following:
Int16 answer = firstNo + secondNo;
into...
Int16 answer = (Int16)(firstNo + secondNo);
Solution 2
Read Eric Lippert 's answers to these questions
Solution 3
Adding two Int16
values result in an Int32
value. You will have to cast it to Int16
:
Int16 answer = (Int16) (firstNo + secondNo);
You can avoid this problem by switching all your numbers to Int32
.
Solution 4
The problem is, that adding two Int16
results in an Int32
as others have already pointed out.
Your second question, why this problem doesn't already occur at the declaration of those two variables is explained here: http://msdn.microsoft.com/en-us/library/ybs77ex4%28v=VS.71%29.aspx:
short x = 32767;
In the preceding declaration, the integer literal 32767 is implicitly converted from int to short. If the integer literal does not fit into a short storage location, a compilation error will occur.
So, the reason why it works in your declaration is simply that the literals provided are known to fit into a short
.
Solution 5
For some strange reason, you can use the += operator to add shorts.
short answer = 0;
short firstNo = 1;
short secondNo = 2;
answer += firstNo;
answer += secondNo;
![m.edmondson](https://i.stack.imgur.com/WC1WD.jpg?s=256&g=1)
m.edmondson
Many of my best answers are written up fully and ported to my blog. This (along with my other abstract ideas) allows me to create an online portfolio of important and interesting information for both referencing and for others to learn from. View my LinkedIn Profile.
Updated on October 31, 2020Comments
-
m.edmondson over 3 years
I wrote the following small program to print out the Fibonacci sequence:
static void Main(string[] args) { Console.Write("Please give a value for n:"); Int16 n = Int16.Parse(Console.ReadLine()); Int16 firstNo = 0; Int16 secondNo = 1; Console.WriteLine(firstNo); Console.WriteLine(secondNo); for (Int16 i = 0; i < n; i++) { //Problem on this line Int16 answer = firstNo + secondNo; Console.WriteLine(answer); firstNo = secondNo; secondNo = answer; } Console.ReadLine(); }
The compilation message is:
Cannot implicitly convert type 'int' to 'short'. An explicit conversion exists (are you missing a cast?)
Since everything involved is an Int16 (short) then why are there any implicit conversions going on? And more specificially why the failure here (and not when initially assigning an int to the variable)?
An explanation would be much appreciated.
-
m.edmondson about 13 yearsConfusing, why is it designed like that? Does this cause problems when adding two
Int64
's together (and they won't fit in the space ofInt32
)? -
myermian about 13 yearsMultiple reasons, some other answers point to posts explaining the why.