Class name conflict importing new package (java)

25,107

If you can't rename your own class, which would be the easiest, then you can circumvent this by not importing the offending class and instead using the fully qualified package name, e.g

org.lwjgl.opengl.Display display = new org.lwjgl.opengl.Display().

Conversely, you should put your own class in packages and never use the default package, so that it's possible to apply the same method to disambiguate your own classes.

Share:
25,107
Cornelius
Author by

Cornelius

Updated on October 14, 2020

Comments

  • Cornelius
    Cornelius over 3 years

    First of all, I am a new to java, so my question might be stupid but i still need an answer :)

    I have a class that handle display matters. I have named it "Display", but the problem is : I need to import a class called org.lwjgl.opengl.Display.

    Of course, I have this error at my Display class statement :

    "Display" is already defined in this compilation unit

    And of course, I can rename my class, but i'd like to be sure there is no way to easily circumvent this issue.

    In a general way (because using a game library such as LWJGL, I guess i will have plenty of this), is it a better idea to prefix all my class to avoid similar label ?

    Update : The class is already in a package.

    package Graphics;
    
    import org.lwjgl.LWJGLException;
    import org.lwjgl.opengl.Display;
    import org.lwjgl.opengl.DisplayMode;
    
    public class Display { ... }
    

    Thanx.

  • JRL
    JRL over 12 years
    @Cornelius: don't import the Display class, use the fully qualified name when you need it, and it will compile.
  • Cornelius
    Cornelius over 12 years
    Ok, i thought it was not a proper way to do this.
  • ADTC
    ADTC almost 11 years
    Does any version of Java have a feature to alias fully qualified names into short names so you don't really have to put the fully qualified name everywhere? Something like import org.lwjgl.opengl.Display as OglDisplay; then OglDisplay display = new OglDisplay(); ?