Compare method throw exception: Comparison method violates its general contract

10,633

If you have two elements when are equal a and b you will get compare(a, b) == -1 and compare(b, a) == -1 which doesn't make any sense.

You can simplify the code with and make it more efficient with

class TimeComparatorTipo0 implements Comparator<DataImportedTipo0> {
@Override
public int compare(DataImportedTipo0 a, DataImportedTipo0 b) {
    String Time1 = a.ora, Time2 = b.ora;

    int cmp = Time1.compareTo(Time2);
    if (cmp == 0) {
       // avoid expensive operations.
       Long VolTot1 = Long.parseLong(a.volume_totale);
       Long VolTot2 = Long.parseLong(b.volume_totale);
       cmp = VolTot1.compareTo(VolTot2);
    }
    return cmp;
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famedoro
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famedoro

Updated on June 04, 2022

Comments

  • famedoro
    famedoro about 2 years

    Possible Duplicate:
    why does my compare method throw exception — Comparison method violates its general contract!

    I've this code:

    class TimeComparatorTipo0 implements Comparator {
    @Override
    public int compare(Object a, Object b) {
         String Time1   = ((DataImportedTipo0) a).ora;
         Long   VolTot1 = Long.parseLong(((DataImportedTipo0) a).volume_totale);
    
         String Time2   = ((DataImportedTipo0) b).ora;
         Long   VolTot2 = Long.parseLong(((DataImportedTipo0) b).volume_totale);
    
        if (Time1.equals(Time2))
        {          
           if ( VolTot1.compareTo(VolTot2) > 0)
             return 1;
           else
             return -1;         
        }
        else
          return Time1.compareTo(Time2);
         }
    };
    

    Sometimes it thrown this exception:

    java.lang.IllegalArgumentException: Comparison method violates its general contract!
    at java.util.TimSort.mergeHi(TimSort.java:868)
    at java.util.TimSort.mergeAt(TimSort.java:485)
    at java.util.TimSort.mergeForceCollapse(TimSort.java:426)
    at java.util.TimSort.sort(TimSort.java:223)
    at java.util.TimSort.sort(TimSort.java:173)
    at java.util.Arrays.sort(Arrays.java:659)
    at java.util.Collections.sort(Collections.java:217)
    at ManageUrl.DownloadUrl.StartThreadDowloadTipo0(DownloadUrl.java:893)
    at ManageUrl.DownloadUpdateWorkflow$ConsumerTipo0.run(DownloadUpdateWorkflow.java:278)
    

    Why ?

    1) how can I avoid it? 2) how can i catch this exception ?

    Thanks in advance.

  • famedoro
    famedoro about 12 years
    Thanks for your response, but I don't understand a thing: when a and b are equals doesn't compare(a, b) is equal to 0 ? AS explained in docs.oracle.com/javase/1.4.2/docs/api/java/util/…
  • Vishy
    Vishy about 12 years
    They should be, but you never return 0. BTW: its best to use Javadoc from Java 7 as Java 6 will be EOL soon. ;)
  • famedoro
    famedoro about 12 years
    Thanks, just a last question: how can i catch this exception using try/catch statement?
  • Vishy
    Vishy about 12 years
    Do you mean try { } catch(IllegalArguementException e) { e.printStackTrace(); } ? Given it a programming error, its not something you can fix at runtime.