Concatenating strings in C, which method is more efficient?

130,353

Solution 1

For readability, I'd go with

char * s = malloc(snprintf(NULL, 0, "%s %s", first, second) + 1);
sprintf(s, "%s %s", first, second);

If your platform supports GNU extensions, you could also use asprintf():

char * s = NULL;
asprintf(&s, "%s %s", first, second);

If you're stuck with the MS C Runtime, you have to use _scprintf() to determine the length of the resulting string:

char * s = malloc(_scprintf("%s %s", first, second) + 1);
sprintf(s, "%s %s", first, second);

The following will most likely be the fastest solution:

size_t len1 = strlen(first);
size_t len2 = strlen(second);

char * s = malloc(len1 + len2 + 2);
memcpy(s, first, len1);
s[len1] = ' ';
memcpy(s + len1 + 1, second, len2 + 1); // includes terminating null

Solution 2

Don't worry about efficiency: make your code readable and maintainable. I doubt the difference between these methods is going to matter in your program.

Solution 3

Here's some madness for you, I actually went and measured it. Bloody hell, imagine that. I think I got some meaningful results.

I used a dual core P4, running Windows, using mingw gcc 4.4, building with "gcc foo.c -o foo.exe -std=c99 -Wall -O2".

I tested method 1 and method 2 from the original post. Initially kept the malloc outside the benchmark loop. Method 1 was 48 times faster than method 2. Bizarrely, removing -O2 from the build command made the resulting exe 30% faster (haven't investigated why yet).

Then I added a malloc and free inside the loop. That slowed down method 1 by a factor of 4.4. Method 2 slowed down by a factor of 1.1.

So, malloc + strlen + free DO NOT dominate the profile enough to make avoiding sprintf worth while.

Here's the code I used (apart from the loops were implemented with < instead of != but that broke the HTML rendering of this post):

void a(char *first, char *second, char *both)
{
    for (int i = 0; i != 1000000 * 48; i++)
    {
        strcpy(both, first);
        strcat(both, " ");
        strcat(both, second);
    }
}

void b(char *first, char *second, char *both)
{
    for (int i = 0; i != 1000000 * 1; i++)
        sprintf(both, "%s %s", first, second);
}

int main(void)
{
    char* first= "First";
    char* second = "Second";
    char* both = (char*) malloc((strlen(first) + strlen(second) + 2) * sizeof(char));

    // Takes 3.7 sec with optimisations, 2.7 sec WITHOUT optimisations!
    a(first, second, both);

    // Takes 3.7 sec with or without optimisations
    //b(first, second, both);

    return 0;
}

Solution 4

size_t lf = strlen(first);
size_t ls = strlen(second);

char *both = (char*) malloc((lf + ls + 2) * sizeof(char));

strcpy(both, first);

both[lf] = ' ';
strcpy(&both[lf+1], second);

Solution 5

They should be pretty much the same. The difference isn't going to matter. I would go with sprintf since it requires less code.

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Xandy
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Xandy

Currently I'm a Computer Science student in Madrid, Spain. Among other things I also play the piano in my free time.

Updated on July 08, 2022

Comments

  • Xandy
    Xandy almost 2 years

    I came across these two methods to concatenate strings:

    Common part:

    char* first= "First";
    char* second = "Second";
    char* both = malloc(strlen(first) + strlen(second) + 2);
    

    Method 1:

    strcpy(both, first);
    strcat(both, " ");       // or space could have been part of one of the strings
    strcat(both, second);
    

    Method 2:

    sprintf(both, "%s %s", first, second);
    

    In both cases the content of both would be "First Second".

    I would like to know which one is more efficient (I have to perform several concatenation operations), or if you know a better way to do it.