Convert function with only AND Boolean operations

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The function you mentioned:

!(A or B) = !A and !B

is the same as:

A or B = !(!A and !B)

So let's start by splitting your problem into two parts of ABC and DEFHRP.

(A and (B or C)) = (A and !(!B and !C))
(D and E and (F or H or R or P)) = (D and E and !(!F and !H and !R and !P))

Since these two parts are joined by an 'or', we can apply the equivalence again to get:

!(!(A and !(!B and !C)) and !(D and E and !(!F and !H and !R and !P)))
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Lukap
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Lukap

Before I was user706780 :-),than Luk ,than ....

Updated on June 19, 2022

Comments

  • Lukap
    Lukap almost 2 years

    I have some function like

    (A and ( B or c)) or (D and E and (F or H or R or P )))
    

    and I want to convert that function to function with only and operations (of course if possible) I find that with DeMorgan's Laws can be done some kind of transformations but I didn't manage to conver this function any ideas ?

    I know that function

    !(A or B) is equal to function !A and !B
    

    but I could not find the equal function to the one above