Debian install netbeans - "No protocol specified"

linux debian java terminal

506

I guest this comes too late, but instead of calling it from root you can try as the normal user with:

sudo ./netbeans-whatever.sh

sudo sh netbeans-whatever.sh

It seems to work also with uninstaller. You can also install as user for the user without using sudo.

506

Lauren

Updated on September 18, 2022

Comments

Lauren over 1 year
So I am a newb to php & mysql. I keep getting this error each time I fill out a form that I created. When I check phpmyadmin to see if the information from the form has been added to the table, it's nowhere to be found. I found a similar question on here and their problem was fixed by running a query to turn the strict mode off of SQL. I tried to do so and it added an entry to the table but all the values in the entry were 0. Here's my php block:
```
<?php

    require('connect2.php');
    session_start();
    $username = $_SESSION['username'];


    //My queries will be here
    $bloodquery = mysql_query("SELECT * FROM `CodesBloodType` ORDER BY `BloodTypeText`");
    $donor_add = "INSERT INTO `Donor`(`DonorID`, `PersonID`, `DateRegistered`, `AgeRegistered`, `DonorPreRegistered`, `MedicalFacilityID`, `NationalLocalRegistry`, `NationalLocalRegistryID`, `Height`, `Weight`, `BloodTypeCode`, `OrganCriteriaID`, `LivingDonor`, `DirectedDonor`) VALUES ($donorid,$personid,$dateregistered,$ageregistered,$donorpreregistered,$medicalfacilityid,$nationallocalregistry,$nationallocalregistryid,$height,$weight,$bloodtypecode,$organcriteriaid,$livingdonor,$directeddonor)";




//Check to see if something is entered in my fields, if so then define variables


// Loop over field names, make sure each one exists and is not empty



$required = array('donorid', 'personid', 'dateregistered', 'ageregistered','medicalfacilityid','nationallocalregistry','nationallocalregistryid', 'height', 'weight','organcriteriaid');
$error = false;
$var = $_POST['submit'];
if($var){
foreach($required as $field) {
  if (empty($_POST[$field])) {
    $error = true;
    if ($error) {
    echo $field. ' is empty';
    ?> 
    <html><br></html>
    <?php
    }
}

  else{
    $error = false;

        }

}

 if(!$error){

    $donorid = $_POST['donorid'];
    $personid = $_POST['personid'];
    $dateregistered = $_POST['dateregistered'];
    $ageregistered = $_POST['ageregistered'];
    if(isset($_POST['donorpreregistered'])){
    $donorpreregistered = "1";}
    else{
        $donorpreregistered = "0";
    }
    $medicalfacilityid = $_POST['medicalfacilityid'];
    $nationallocalregistry = $_POST['nationallocalregistry'];
    $nationallocalregistryid = $_POST['nationallocalregistryid'];
    $height = $_POST['height'];
    $weight = $_POST['weight'];
    $bloodtypecode = $_POST['bloodtypec'];
    $organcriteriaid = $_POST['organcriteriaid'];
    if(isset($_POST['livingdonor']))
    {
        $livingdonor = "1";
    }
    else{
        $livingdonor = "0";
    }

    if(isset($_POST['directeddonor'])){
    $directeddonor = "1";}
    else{
        $directeddonor = "0";
    }




    $result = mysql_query($donor_add);
    if (!$result) {
    die('Invalid query: ' . mysql_error()); 
    //echo "Form Submitted Successfully";    

        }
    }

}   



?>
```
Invalid query: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ',,,,,,,,,,,,)' at line 1
- FooBee almost 13 years
  
  I guess you don't run this either in an X session or with ssh -X? If it complains about a missing DISPLAY variable, it appears to need a GUI, which you are likely lacking or the variable would be present.
- hmontoliu almost 13 years
  
  You meant export DISPLAY=:0.0 not extract DISPLAY=:0.0, don't you?
- David almost 13 years
  
  yes i meant export
- John Conde about 9 years
  
  In the future always post the error message. Not all of us are mind readers.
- Saagar Elias Jacky about 9 years
  
  do you really need all those single quotes inside the INSERT statement? - just curious...
- Lauren about 9 years
  
  Will do. Invalid query: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ',,,,,,,,,,,,)' at line 1
- John Conde about 9 years
  
  Your values are obviously missing! How do you not see this?
- Lauren about 9 years
  
  Please explain like I'm 5. I do not understand.
- Jay Blanchard about 9 years
  
  Please, stop using mysql_* functions. They are no longer maintained and are officially deprecated. Learn about prepared statements instead, and use PDO.
- Jay Blanchard about 9 years
  
  See all of the commas next to each other in the error @Lauren? There should be a value between each one.
- Marc B about 9 years
  
  You're treating PHP like it can time travel. You're executing your INSERT query BEFORE you defined any of the variables that hold the values you're trying to insert.
- newfurniturey about 9 years
  
  @SaagarEliasJacky Those aren't single quotes, they're backticks; it's an identifier quote character in mysql to mark table and column names =]
- Michael Berkowski about 9 years
  
  At the time the variable $donor_add is created, all the field variables to populate it from $_POST have not yet been given values. The $donor_add = "INSERT...." needs to be done after all the vars are populated, just before mysql_query().
- Jay Blanchard about 9 years
  
  $donorid,$personid,$dateregistered,$ageregistered,$donorprer‌egistered,$medicalfa‌cilityid,$nationallo‌calregistry,$nationa‌llocalregistryid,$he‌ight,$weight,$bloodt‌ypecode,$organcriter‌iaid,$livingdonor,$d‌irecteddonor are not populated. You need to move your query a place in the code after the variables have been set.
- Lauren about 9 years
  
  Thank you for the clarification @MichaelBerkowski :)
- halfer about 9 years
  
  In addition to the feedback already given, you should be seeing notices/warnings in your development environment to alert you to the fact that variables are being read without being defined. If you don't see them, it is possible they are turned off in your PHP configuration. Try adding error_reporting(-1); at the start of your script temporarily (don't add this to live, but it is helpful during development).
Falcon Momot over 8 years

Running X as root?!