Determine If Business Is Open/Closed Based On Business Hours
Solution 1
You would first need to create an array which will hold your days of the week, and their respective close/open time range(s).
/**
* I setup the hours for each day if they carry-over)
* everyday is open from 09:00 AM - 12:00 AM
* Sun/Sat open extra from 12:00 AM - 01:00 AM
*/
$storeSchedule = [
'Sun' => ['12:00 AM' => '01:00 AM', '09:00 AM' => '12:00 AM'],
'Mon' => ['09:00 AM' => '12:00 AM'],
'Tue' => ['09:00 AM' => '12:00 AM'],
'Wed' => ['09:00 AM' => '12:00 AM'],
'Thu' => ['09:00 AM' => '12:00 AM'],
'Fri' => ['09:00 AM' => '12:00 AM'],
'Sat' => ['12:00 AM' => '01:00 AM', '09:00 AM' => '12:00 AM']
];
You then loop over the current day's time range(s) and check to see if the current time or supplied timestamp is within a range. You do this by using the DateTime class to generate a DateTime object for each time range's start/end time.
The below will do this and allow you to specify a timestamp in case you are wanting to check a supplied timestamp instead of the current time.
// current or user supplied UNIX timestamp
$timestamp = time();
// default status
$status = 'closed';
// get current time object
$currentTime = (new DateTime())->setTimestamp($timestamp);
// loop through time ranges for current day
foreach ($storeSchedule[date('D', $timestamp)] as $startTime => $endTime) {
// create time objects from start/end times
$startTime = DateTime::createFromFormat('h:i A', $startTime);
$endTime = DateTime::createFromFormat('h:i A', $endTime);
// check if current time is within a range
if (($startTime < $currentTime) && ($currentTime < $endTime)) {
$status = 'open';
break;
}
}
echo "We are currently: $status";
See DEMO of above
Solution 2
Modified from the accepted answer for use on a AWS Debian Server (located on the west coast) where our store hours are actually EST... also dropped into a PHP function.
/*
* decide based upon current EST if the store is open
*
* @return bool
*/
function storeIsOpen() {
$status = FALSE;
$storeSchedule = [
'Mon' => ['08:00 AM' => '05:00 PM'],
'Tue' => ['08:00 AM' => '05:00 PM'],
'Wed' => ['08:00 AM' => '05:00 PM'],
'Thu' => ['08:00 AM' => '05:00 PM'],
'Fri' => ['08:00 AM' => '05:00 PM']
];
//get current East Coast US time
$timeObject = new DateTime('America/New_York');
$timestamp = $timeObject->getTimeStamp();
$currentTime = $timeObject->setTimestamp($timestamp)->format('H:i A');
// loop through time ranges for current day
foreach ($storeSchedule[date('D', $timestamp)] as $startTime => $endTime) {
// create time objects from start/end times and format as string (24hr AM/PM)
$startTime = DateTime::createFromFormat('h:i A', $startTime)->format('H:i A');
$endTime = DateTime::createFromFormat('h:i A', $endTime)->format('H:i A');
// check if current time is within the range
if (($startTime < $currentTime) && ($currentTime < $endTime)) {
$status = TRUE;
break;
}
}
return $status;
}
Solution 3
You should regroup all opening hours in a array since the openings hours of yesterday could be of influence if you stay opened after midnight. Also having the possibility to have several opening hours per day might be handy.
<?php
$times = array(
'mon' => '9:00 AM - 12:00 AM',
'tue' => '9:00 AM - 12:00 AM',
'wed' => '9:00 AM - 12:00 AM',
'thu' => '9:00 AM - 12:00 AM',
'fri' => '9:00 AM - 1:00 AM',
'sat' => '9:00 AM - 1:00 PM, 2:00 PM - 1:00 AM',
'sun' => 'closed'
);
function compileHours($times, $timestamp) {
$times = $times[strtolower(date('D',$timestamp))];
if(!strpos($times, '-')) return array();
$hours = explode(",", $times);
$hours = array_map('explode', array_pad(array(),count($hours),'-'), $hours);
$hours = array_map('array_map', array_pad(array(),count($hours),'strtotime'), $hours, array_pad(array(),count($hours),array_pad(array(),2,$timestamp)));
end($hours);
if ($hours[key($hours)][0] > $hours[key($hours)][1]) $hours[key($hours)][1] = strtotime('+1 day', $hours[key($hours)][1]);
return $hours;
}
function isOpen($now, $times) {
$open = 0; // time until closing in seconds or 0 if closed
// merge opening hours of today and the day before
$hours = array_merge(compileHours($times, strtotime('yesterday',$now)),compileHours($times, $now));
foreach ($hours as $h) {
if ($now >= $h[0] and $now < $h[1]) {
$open = $h[1] - $now;
return $open;
}
}
return $open;
}
$now = strtotime('7:59pm');
$open = isOpen($now, $times);
if ($open == 0) {
echo "Is closed";
} else {
echo "Is open. Will close in ".ceil($open/60)." minutes";
}
?>
On the other hand if you only want to resolve the problem with time like 9am - 5am
you should check if $from > $to
and add 1 day to $to
if necessary.
Solution 4
A bit late but I have a solution for others, if the one's here don't quite fit their needs. I do like the solution of having multiple time sets for days that close after midnight but then this would add extra data handling to display the hours. You would first have to check if there are multiple time sets available then confirm that they are connected (no time in between).
My solution was instead to write a function that you pass the opening time, closing time, and time-in-question and it will return true for open and false for closed:
function is_open($open, $close, $query_time){
$open = new DateTime($open);
$close = new DateTime($close);
$query_time = new DateTime($query_time);
$is_open = false;
//Determine if open time is before close time in a 24 hour period
if($open < $close){
//If so, if the query time is between open and closed, it is open
if($query_time > $open){
if($query_time < $close){
$is_open = true;
}
}
}
elseif($open > $close){
$is_open = true;
//If not, if the query time is between close and open, it is closed
if($query_time < $open){
if($query_time > $close){
$is_open = false;
}
}
}
return $is_open;
}
Stephen
Updated on September 14, 2020Comments
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Stephen over 3 years
My code works fine if the times are AM to PM (Ex: 11 AM - 10 PM), but if the locations hours of operation are AM to AM (Ex: 9 AM - 1 AM) it breaks. Here is my code:
$datedivide = explode(" - ", $day['hours']); //$day['hours'] Example 11:00 AM - 10:00 PM $from = ''.$day['days'].' '.$datedivide[0].''; $to = ''.$day['days'].' '.$datedivide[1].''; $date = date('l g:i A'); $date = is_int($date) ? $date : strtotime($date); $from = is_int($from) ? $from : strtotime($from); $to = is_int($to) ? $to : strtotime($to); if (($date > $from) && ($date < $to) && ($dateh != 'Closed')) { ?> <script type="text/javascript"> $(document).ready(function(){ $('.entry-title-container').append('<div class="column two"><h2 style="color:green;text-align: left;margin: 0;">OPEN<br /><span style="color:#222;font-size:12px;display: block;">Closes at <?php echo $datedivide[1]; ?></span></h2></div><br clear="all" />'); }); </script> <?php }
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Stephen about 11 yearsCould you give me an example on how I can integrate this to my script?
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Baba about 11 years+ Nice but i would have preferred if you used
DateTime
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Daniel P over 10 yearsOnly downside with this is that the opening hours are hard-coded.
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RamenChef over 7 yearsCare to elaborate?
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Marty Demichele over 7 yearsFirst define $startTime and $endTime in the array
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Marty Demichele over 7 years$monsta = "07:00 AM"
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RamenChef over 7 yearsCan you edit that into the answer rather than posting it in the comments?
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Jayvirsinh Vaghela almost 6 yearshow to fetch data as this kind of array?
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Jayvirsinh Vaghela almost 6 yearshow to store and fetch data to get this type of array?
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creg over 5 yearsIt is recommended to set the current time zone, e.g.
date_default_timezone_set('Europe/Berlin');
. Otherwise there is a risk that the time provided by DateTime is not correct, e.g. -2 h. -
cryptic ツ over 5 years@creg you should be passing the timezone to DateTime, not changing the default timezone. It's best to use UTC for all dates/times and only supply a timezone in the instances you need the UTC value converted to a local time.
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peterxz over 5 yearsHow could you make the opening times not hard-coded? I want to be able to change the times on the fly as well as dynamically add exceptions, how would I be able to do this? (I mean in terms of storage, as the array would always go back to the "default" state which is not desirable)
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Loosie94 over 3 yearsLove this solution, but how do I make this the Europe (24-hours) way?
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sdforet over 3 years@Loosie94, you would adjust the format in each location to use the format you need for comparison (the 'h:i A') note you will also need to update the store schedule array to 24hr time.... The array times get converted to objects for comparision in the foreach loop so these formats have to match. Then just update the DateTime parameter assigned to $timeObject variable to your timezone. Reference for DateTime->fomat() Hope this helps.
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Loosie94 over 3 years@sdforet, I figured the only thing I had to do was (indeed) changing the times to 24-hours, change the lowecase h in $startTime and $endTime to uppercase and remove the A in all H:i A formats. Working good now, thanks!